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Unreachable Code

 
Greenhorn
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The above code will give Unreachable code error on the println statement
Why not the below code

show() will throw the Exception in all case. so the println() wont be reachable.But why the compiler didnt give the error.

Thank you!!
 
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show declares Exeption, so in the code (calling method) is seen as " maybe there's an Exception",

instead throw is seen as "there's an Exception" and it's similar to a return statement.
 
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1st case: you are throwing an exception in the main method and that will go straight to your catch block which will not allow your "kk" to be printed.

2nd case: you are calling the show method which which in the compiler terms "might or might not" throw an Exception so it thinks System.out can be reached.
 
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Welcome to JavaRanch, P Ventura
 
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while compiling the program the compiler dose not know whether the method show will or will not throw an exception thus it dose not complain...
 
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