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Short circuit operator problem

 
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Hi All,

I have the following two code snippet.

A)
B)

A gives 'Value of i : 1'
B gives 'Value of i : 2'
For A the first condition before || evaluates to true and hence short circuits the whole expression. But the short circuit does not happen for B where first condition before && evaluates to false. Please explain.

Thanks in advance,
Amit
[ December 26, 2007: Message edited by: Amit Ghai ]
 
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This is how it calculates
A) int i = 0;
if((++i > 0) || (++i > 1 && ++i > 5))
{}
System.out.println("Value of i : " + i);
and so the val of i becomes 1 now coming to B)

B)
int i = 0;
if((++i > 4 && ++i > 1) || (++i > 5))
{}
System.out.println("Value of i : " + i);
and so since in first condition (++i > 4 && ++i > 1) the first part returns false which makes the whole condition to return false and now since you have an || it evaluates the 2nd condition after the || which is ++i>5. So the value of i is evaluated twice and so the result 2. I hope you understood
 
Amit Ghai
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I missed the point on operator precedence. This SCJP preparation is killing me

http://java.sun.com/docs/books/tutorial/java/nutsandbolts/operators.html

Thanks for the reply.
 
Don't get me started about those stupid light bulbs.
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