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Floating Point Number and dividebyzero arithmatic exception

 
Greenhorn
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Why does the Floating Point numbers does NOT produce the dividebyzero arithmatic exception ??



The above code runs fine, But Why ?? Why is it designed like that ?? It should through an exception...

Any Thgoughts ?

Regards
Veer
 
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Because IEEE 754 specifies that division by zero for floating point numbers should result in either positive or negative infinity depending on the sign bit.
 
Ranch Hand
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* if the value of the divisor in floating-point division is 0 no exception is thrown; the value of the results are as follows:
o division of a positive floating-point value: POSITIVE_INFINITY
o division of a negative floating-point value: NEGATIVE_INFINITY
o division of a floating-point value by -0: POSITIVE_INFINITY

 
veer jain
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Thanks a ton Guys !!
 
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