in switch case some confusion

[pawni jain]

hello,
program that i made very basic but there is difference in output for char and int expression.
Please look at following code

class Switchtestint
{
public static void main(String args[])
{
int a=7;
switch(a)
{
case 1: System.out.println("1");
default: System.out.println("default");
case 2: System.out.println("2");
case 3: System.out.println("3");
}
}
}

output:
default
2
3


class Switchtest
{
public static void main(String args[])
{
char cha='z';
switch(cha)
{
case 'a': System.out.println("a");
default: System.out.println("default");
case 'b': System.out.println("b");
case 'z': System.out.println("z");
}
}
}


output:
z



Why is it so??

thanks

[balajee annamalai]

In case a,Since the value 7 is not avaliable in case statement it prints the value in default and since there is no break avaliable in default it prints both case 2 and 3.

But in the case of example b, The output is straight forward since z is avaliable in a case 'z': it just prints z.

[Tarun Kumar]

Output is right.

in first sceanario
int a=7;
switch(a)
{
case 1: System.out.println("1");
default: System.out.println("default");
case 2: System.out.println("2");
case 3: System.out.println("3");
}
}

since their id no match for the a(7) hence it will go in the default case,after which break statement is not their hence it will fall throw all case.

in first sceanario
char cha='z';
switch(cha)
{
case 'a': System.out.println("a");
default: System.out.println("default");
case 'b': System.out.println("b");
case 'z': System.out.println("z");
}
}

since their is exact match for cha('z') hence it will not go in the default case.it will go in the case 'z',and since it is the last case output is z

hope you will get.need further clarification the ask

[pawni jain]

Thanks Balajee n Tarunjava