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Overload methods?

 
Greenhorn
Posts: 24
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Can we call byte or long version through overloading in this code snippet?

public class over{
public void first(int a,int b) {
System.out.println("first is:"+(a+b));
}
public void first(long a,long b) {
System.out.println("second is:"+(a+b));
}
public void first(byte a,byte b) {
System.out.println("third is:"+(a+b));
}

public static void main(String a[]) {
over aa = new over();
aa.first(1,1);

}
}


If Yes, How? :roll:
 
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If you pass byte or long parameters it will get the appropriate one. Otherwise it gets the int version .
 
Greenhorn
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To invoke the long method:

aa.first(1L,1L);

There is no short-cut for byte equivalent to the L notation. To invoke the byte method you will have to explicitly cast the parameters:

aa.first((byte)1,(byte)1);
 
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