method overloading

[Matiz Dave]

public class TestOverloading1 {
public static void main(String arg[]){
TestOverloading1 to=new TestOverloading1();
to.methodA(null);
}
private void methodA(Object o1){
System.out.println("into Object");
}
private void methodA(String s1){
System.out.println("into String");
}
}

The above code prints "into String". How does java interpret null? How does the method having String argument get called?

[Henry Wong]

Basically, Java chooses the most specific method, if it finds more than one overloaded method that matches the signature. Here is an excerpt from the JavaRanch FAQs that explains it...

http://faq.javaranch.com/java/ScjpFaq#mostSpecific

Henry

[Matiz Dave]

Thanks, Henry

How is null evaluated? How is it more specific to a String object as compared to Object object?

[Henry Wong]

Originally posted by Matiz Dave:
Thanks, Henry

How is null evaluated? How is it more specific to a String object as compared to Object object?

If the FAQ is not sufficient enough to explain what is the "most specific method", I suggest that you do a search on this forum. This is a very often asked question -- and has been answered many times.

Henry

[Don Solomon]

More often, an ambiguity error will occur when the code is compiled. Try String and Integer.

[Ninad Kulkarni]

Because both String and Integer are specific to each other so ambiguity occurs


Regards
Ninad

[Jayati Das]

As String is a subtype of Object so it is more specific than Object and so it gets choosen in this case .