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Encapsulation??

 
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Sorce: K&B Book.

1. public class B extends A {
2. private int bar;
3. public void setBar(int b) {
4. bar = b;
5. }
6. }
7. class A {
8. public int foo;
9. }

The question is whether class B is tightly encapsulated??
The correct answer is No.
I agree that B extends A, but it does not use the public variable foo of A, then shouldnt it be tightly encapsulated???
 
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I think its because foo in A is public. So it can be accessed directly using any reference of A or it's sub-types.

So you can do this

B obj = new B();
obj.foo = 20;//encapsulation broken

I think this is the reason...
 
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Yes. I agree with Ankit.
 
Abhi vijay
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That means, if a superclass is not tightly encapsulated,then none of its sub classes can be tightly encapsulated,right??
 
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yes this is right, if super class is tightly encapsulated then only its subclasses are tightly encapsulated
 
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