MH
I've heard it takes forever to grow a woman from the ground
Originally posted by Joseph George:
IAMNW?
MH
Originally posted by Maxim Katcharov:
so if abcd = efgh, F is within ijkl, and it's simple from there, otherwise try for:
abcd > efgh
abef vs cdTT
>7)If abef weighs more again,counterfeit is between a and b.
>8)If abef weighs less,counterfeit is between c and d.
>9)If abef weighs same as cdkl,counterfeit is between g and h.
I've heard that there are a number of distinct ways to do this. This is the second I've seen.
MH
Originally posted by shankar vembu:
am i missing something
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2)abcd weighs more than efgh.Exchange d and e and replace fgh with jkl(true coin).If abce again weighs more,false coin is between abc.If abce weighs less,false coin is between d and e.
Is this right? or something is missing?
Originally posted by Vijay Vaddem:
Else, pick out the collection of 3 balls (either ABC or DEF, whichever is
lighter in total); from these three balls, pick up 2 balls
and measure the weight. U should get the odd one....
Originally posted by Maxim Katcharov:
You didn't state any results with the false coin being amidst fgh. If it doesn't work, you're about one step of logic away from the solution I got...
MH
Sometimes the only way things ever got fixed is because people became uncomfortable.
Originally posted by Tim Holloway:
You do realize that this is just a HeapSort in disguise, don't you?![]()
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