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Reverse 5 digit number by multiplying 4

 
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A, B, C, D and E are 5 different single digit numbers. The number ABCDE times 4 will have a result of EDCBA. What digit numbers do A, B, C, D, and E represent?

ABCDE
* 4
-------
EDCBA
-------
 
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21978
 
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Could any one tell me what is the logic to calculate this problem. Atleast direct others how to calculate this problem or tell the algorithm to solve it....
 
Garrett Rowe
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Originally posted by Ankur Sharma:
Could any one tell me what is the logic to calculate this problem. Atleast direct others how to calculate this problem or tell the algorithm to solve it....



21978 * 4 = 87912

I just used a simple loop from 10000 to 99999 and multiplied each number by 4, converted to a String, and checked to see if the String reversed was equal to the original number as a String.
 
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Originally posted by Ankur Sharma:
Could any one tell me what is the logic to calculate this problem. Atleast direct others how to calculate this problem or tell the algorithm to solve it....



You could look at it as an integer linear programming problem.

Find A,B,C,D,E such that.

A*10000 + B*1000 + C*100 + D*10 + E = 4*(E*10000 + D*1000 + C*100 + B*10 + A)
- or -
A*9996 + B*960 - C*300 - D*3990 - E*39999 = 0
A >= 0
A <= 9
B >= 0
B <= 9
C >= 0
C <= 9
D >= 0
D <= 9
E >= 0
E <= 9
 
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- A can only be 1 or 2
if A > 2 then the answer would be of the form FEDCBA


-let's try with A = 1
1BCDE
*4
------
EDCB1

impossible : 4*E = some number ending by 1

- then A "MUST" be 2
2BCDE
*4
-----
EDCB2


- E=3 or E=8 (E*4 has to be a number ending with 2)

let's try E=8 (looks like the easier...)

2BCD8
*4
-----
8DCB2


- B can only 1 or 2 (otherwise 4*B > 10 and that's now impossible)
Since we already have a 2 , b=1

21CD8
*4
-----
8DC12


- we can write : D*4 + 3 = some number ending by 1
->D*4 = some number ending by 8

D=2 or D=7 => D=7 (A = already 2)


21C78
*4
-----
87C12


- (4*21000 = 84000)
we can write

C78
*4
-----
3C12

we can write C*4 + 3 = 3C (beware 3C means thirty C)
so C >= 7
we already have a 7 and a 8 => C = 9

21978
*4
-----
87912


No computer needed to do this...
 
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A great performance-improvement would be to reduce the loop to unique digits in the numbers:
 
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Microsoft's VBA:

For x = 10000 To 25000
   a$ = Trim(Str(x))
   Reverse_a$ = ""
   For y = Len(x) To 1 Step -1
       Reverse_a$ = Trim(Reverse_a$ + Mid(a$, y, 1))
   Next
   If Reverse_a$ = Trim(Str(x * 4)) Then MsgBox (a$)
Next x
 
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Welcome to the Ranch That looks good for a solution with a loop. I trust it took you less than 15 years to find
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