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Unicode Charater Literals

 
Greenhorn
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Hi Everybody,
Examine this code
char x = '\u000a';
System.out.println(x);
When I compile this I get Errors as in
Invalid character constant.
char x = '\u000a';
^
';' expected.
char x = '\u000a';
^
Invalid character constant.
char x = '\u000a';
even when I comment the Line char x = '\u000a';
I get an error. This error is not seen if I replace the 'a' with any of the other alphabets....
I can't seem to figure why this is happening.
If someone could please throw some light on this topic...
Thanx in Advance
Sheldon:-)

 
Ranch Hand
Posts: 202
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I remembered reading about this before, and I found it. Gotta give credit where it's due... this is thanks to Sheriff Maha Anna.
"The compiler acts according to the Java lang spec.
From JLS
--------
Because Unicode escapes are processed very early, it is not correct to write '\u000a' for a character literal whose value is linefeed (LF); the Unicode escape \u000a is transformed into an actual linefeed in translation step 1 (�3.3) and the linefeed becomes a LineTerminator in step 2 (�3.4), and so the character literal is not valid in step 3. Instead, one should use the escape sequence '\n' (�3.10.6). Similarly, it is not correct to write '\u000d' for a character literal whose value is carriage return (CR). Instead, use '\r'."
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