What is the mystery ?

[asheesh talwar]

When I run the following program in text pad (I have jdk1.1.7(IBM)on NT) I gets O/P as 10 & when the same program is run with VAJ3.0 on NT I gets O/P as 10.0
Can any one explain the mystery ?
If I have following choices then what I should I pick for such type of questions ?
a) Compiler error
b) Runtime exception
c) 10
d) 6.0
e) 10.0
class X {
public static void main(String[] a) {
System.out.println(9 > 8?10:6.0);
}
}

Cheers
Ashish

[Jim Yingst]

Note that there have already been several useful responses to your same question over at Marcus' site. But perhaps others can add something as well...
[This message has been edited by Jim Yingst (edited December 28, 2000).]

[jatin rai]

dear asheesh
See basically your o/p is in the integer form. While the Sop (System.out.println) takes a String class object as it's parameter or in simpler words u must pass on a string value to Sop method. Now when the answer to the argument passed is evaluated it comes out to be 10. now the JVM finds that the answer is in the integer format & not the compiler format. to this the interpreter calls the toString() method or the valueOf() method. this converts 10 to "10" & gives the o/p. but dear acc to me it depends on the valueOf() method. on one ocassion it might have called the valueOf(int) & on the other ocassion iot might have called valueOf(double) & given th o/p as 10.0

[Son Le]

Asheesh,
I think the aswer would be 10.0. 10 is promoted to a double since the operation involves 6.0, which is a double.