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What operator is this: |= ?

 
Greenhorn
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I found this in the code i'm doing maintenance:

boolean draw = false;
//some code
draw |= x.equals(a) &&(Integer.parseInt(c)>=Integer.parseInt(d));

It compiles fine... but doesn't do what it supossed to do. I already correct it, but i'm not sure what exactly is "|=" (and is not "!="). Any ideas?
 
Marshal
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A compound assignment operator with | which is the bitwise [inclusive] OR and = which is assignment.
 
Java Cowboy
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The notation "x #= y" where # is an operator like +, -, *, /, |, & is a shorthand way of writing "x = x # y".

So, in your case: draw |= ... means: draw = draw | ...
 
Greenhorn
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Hi,

'|' operator is a pipe operator and it is used to perform 'logical OR' operation. It is one of the logical operators in Java.

When used with compound statement like
x |= y it is to be read as x = x | y

Bye TC
 
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