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Exceptions - throws and try, catch..

 
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Hi,
As I understand, the throws clause is used in the method
declaration indicating that the method being created might throw an exception(which is being declared) and the application/program using this method should be able to handle it.
Now, my questions are:
1. Since we always code try and catch for an exception we want
to handle inside the method being created, why do we have
to mention throws in the method/class declaration and let
other methods/classes handle the exception?
2. If the above case is true, why do we need to have throws
clause at all, if we are able to handle all the exceptions
using try and catch?
Am I making sense here? Please clarify my doubts.
Thanks
 
Desperado
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If the method handles the checked exception by itself, it doesn't have to declare that it throws it.
 
Anonymous
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Then, in what scenarios, exactly do we have to use Throws clause?
Thanks.
 
Tony Alicea
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When the methods throws a checked exception and does not catch it in a try/catch block, it must declare it in its <CODE>throws</CODE> clause.
 
Wanderer
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Although you can catch an exception as soon as it's thrown, sometimes it's much more convenient to catch it in one of the outer calling functions. You have the option to defer handling to an outer function; if you do, you must declare the exception in a throws clause.
 
Anonymous
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Thanks Jim, Your answer cleared my doubt, about the use of throws clause.
 
Ranch Hand
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I know we can have
try with couple differnt catch.
How about having 2 try block?
I can't get it compile but it doesn't make sense to me.
Any one can explain for that? Thanks!
 
mister krabs
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Why would you need two try blocks? What would that buy you?
Another reason for declaring a throws is that you may generate the exception yourself!
 
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