I thought I understood this stuff.....

[David Leland]

I was practicing from Dan Chisholm's java tests and came across this question.

  public static void main(String args[]) {
    int x = 6;
    int success = 0;
    do  {
      switch(x) {
        case 0: System.out.print("0");
          x += 5; break;
        case 1: System.out.print("1");
          x += 3; break;
        case 2: System.out.print("2");
          x += 1; break;
        case 3: System.out.print("3");
          success++; break;
        case 4: System.out.print("4");
          x -= 1; break;
        case 5: System.out.print("5");
          x -= 4; break;
        case 6: System.out.print("6");
          x -= 5; break;
        default: System.out.print("Default ");
      }
    } while ((x != 3) || (success < 2));
  }

Here's my question. During the 3rd loop the variable "x" is set to 3. success is still 0. Shouldn't the loop stop since x is 3??
Any insight would in helpful...

[Bosun Bello]

The loop will not stop because of this statement.
while ((x != 3) || (success < 2))
You are saying the loop should continue as long as one of the conditions is true.
You need to use &&
while ((x != 3) && (success < 2));

[David Leland]

DOH!
Ok - I guess studying all this stuff is messing with my mind. Thanks for the clarification.