IndexOutOfBoundsException

[Wang Yang]

When I access a ArrayList by get()
I got the following exception
"IndexOutOfBoundsException index 80 size 100"
I refer to the source code of java.util.ArrayList

if (index >= size || index < 0)
    throw new IndexOutOfBoundsException(
"Index: "+index+", Size: "+size);

But from the exception info,we know the index<size
What's wrong with it?
Thanks in advance!
[ May 09, 2004: Message edited by: Wang Yang ]

[Stefan Krompass]

Hi,
can you post a minimal sample of your code where the exception occurs?
cu
Stefan
[ May 09, 2004: Message edited by: Stefan Krompass ]

[David Peterson]

(index >= size || index < 0)

If index = 80 and size = 100 then the condition will not evaluate to true, so the exception will not occur. So... perhaps index is not really 80 (e.g. maybe it's -80) or size is not really 100 (e.g. maybe it's 10) or your JVM has been hit by a stray cosmic ray.
Or are you using it in a multi-threaded application? The methods in ArrayList are not synchronized, so it is possible (though you'd have to be reasonably unfortunate) that another thread updates the list at the same time as you're getting its contents. If this is the case, either synchronize or use a Vector instead.

[Wang Yang]

Originally posted by David Peterson:

(index >= size || index < 0)

If index = 80 and size = 100 then the condition will not evaluate to true, so the exception will not occur. So... perhaps index is not really 80 (e.g. maybe it's -80) or size is not really 100 (e.g. maybe it's 10) or your JVM has been hit by a stray cosmic ray.
Or are you using it in a multi-threaded application? The methods in ArrayList are not synchronized, so it is possible (though you'd have to be reasonably unfortunate) that another thread updates the list at the same time as you're getting its contents. If this is the case, either synchronize or use a Vector instead.

Thank you every much!
It is the trap of Multi-thread.
I'll pay more attention to it.