how to convert string to short

[Sanjul Jain]

how can i convert string to short in java.

thanks in advance,
sanjul

[Rene Larsen]

short s = Short.parseShort(String);

Rene

[Sanjul Jain]

thanks for your reply, but its not working. this is what i have done:

  public static void main (String[] args) throws IOException {
 
   
   short s= 0;
   
   String g = "1test";     
try {
  s = Short.parseShort(g);
  //s = (short)Integer.parseInt(g.trim(), 16);
  System.out.println(s);
} catch (NumberFormatException e){}     
      System.out.println("exception");
       
        }
  

I need to print the value of s.


Regards,
Sanjul

[Giovanni De Stefano]

Hi Sanjul,
please make up your mind with what you are trying to do.

You asked in your first post how to convert a string into a short, and Rene told you how to do it properly.
Then, in your second post you say that you need the value of 's' BUT you are parsing a string into a Short WITHOUT noticing that the string itself CANNOT be recognized as a number because it is 'ltest' !!!

Here is a WORKING example:

public class Test {
 
    public static void main(String[] args) {
        short s = 0;
        String g = "24";
        try {
            s = Short.parseShort(g);
            System.out.println(s);
        } catch (NumberFormatException e) {
            System.err.println("The string is not properly formatted!");
        }                
    }
}

Try with g = "24" and, for example, g = "24a".

Giovanni

[Layne Lund]

Originally posted by Sanjul Jain:
thanks for your reply, but its not working. this is what i have done:

  public static void main (String[] args) throws IOException {
 
   
   short s= 0;
   
   String g = "1test";     
try {
  s = Short.parseShort(g);
  //s = (short)Integer.parseInt(g.trim(), 16);
  System.out.println(s);
} catch (NumberFormatException e){}     
      System.out.println("exception");
       
        }
  

I need to print the value of s.


Regards,
Sanjul

You should post what happens when you run this example. I would guess that you are seeing the output when from the catch clause because an exception is thrown. The problem is that the String "1test" cannot be parsed to a short because it has non-numerical characters in it.

For future reference, it would be more helpful to do something like

ex.printStackTrace();

in the catch clause. This will give you some helpful information when you an exception occurs unexpectedly in your program.

HTH

Layne