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methods and return type

 
Ranch Hand
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need help in identifying the right method and return type in my program.thanks for ever listening hears.

code:

public class QuadraticEquation{
public static double Equation(int a,int b,int c){
double D,x1,x1;
//int a,b,c;
D=(Math.pow(b,2)-4*a*c);
if(D=0){
x1=(-b-Math.sqrt(D))/(2*a);
x2=(-b+Math.sqrt(D))/(2*a);
return(x1,x2);
}
}
public static void main(String arg[]){
int a=1;
int b=-3;
int c=2;
QuadraticEquation g=new QuadraticEquation();
System.out.println(g.Equation(a,b,c));
}
}
 
Ranch Hand
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Hi all,

you cannot return multiple values. In your case you should return an array of doubles.
Your method could be like:




Yours,
Bu.
 
Java Cowboy
Posts: 16084
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There are some more bugs in your code. For example:

if(D=0){

This is not going to do what you want. It assigns 0 to D. To compare values, use == instead of =.

Quadratic equations do not always have two solutions. What are you going to return if the equation does not have any (real) solutions (when D < 0)?
 
oghenekaro EFEKODO
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i corrected my mistake and add the array method,compiled with no error,but the problem now is that the program just keep runnin with no result.please what do i do next to correct this problem.
the cod again is

public class QuadraticEquation{
public static double [] Equation(int a,int b,int c){
double [] array=new double[2];
double D,x1,x2;
//int a,b,c;
D=(Math.pow(b,2)-4*a*c);
for(int i=0;1<array.length;i++){
if(D==0){
x1=(-b-Math.sqrt(D))/(2*a);
x2=(-b+Math.sqrt(D))/(2*a);
}
}
return array;
}
public static void main(String arg[]){
int a=1;
int b=-3;
int c=2;
QuadraticEquation g=new QuadraticEquation();
System.out.println(g.Equation(a,b,c));
}
}
 
Ranch Hand
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for(int i=0;1<array.length;i++)

have a closer look at this line. Should not be to
difficult to spot the mistake
 
oghenekaro EFEKODO
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please couldn't locate the problem in

for(int i=0;i<=array.length;i++)


i tried but my best wasn't good enough.please somebody help me,am so shy for not finding what the problem really is.thanks again for your ever listening hears.
 
author and iconoclast
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An array "array" has array.length elements in it. The first one is array[0]; the last one is array[array.length - 1]. If you try to access array[array.length], that's off the end of the array and you'll get an ArrayIndexOutOfBoundsException .
 
oghenekaro EFEKODO
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i added array[array.length-1] and gave an Exception in thread "main" java.lang.NoClassDefFoundError:QuadraticEquation.

so what do i do next.thanks for your ever listening hears
 
Ernest Friedman-Hill
author and iconoclast
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Classpath issues, I imagine. Just start your program with

java -cp . QuadraticEquation

That's "java space dash cp space dot space QuadraticEquation".

I'm afraid, based on this last question, that this really needs to be moved to Java in General (Beginner) -- so off it goes.
 
With a little knowledge, a cast iron skillet is non-stick and lasts a lifetime.
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