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output is:

Prints: A0B0A1B1A1B2

why A1 prints twice here....?
Can you explain this?
 
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In new A().new B(); case it will print A0B0 is ok.
Then as in getCounter() and getInnerCounter() post increment operators are used.Then Counter and InnerCounter is set to 1.
But then A a1 = new A();constructor is used only once so,Counter only incremented once
and So A1 is printed twice
but as a1.new B(); // 3
a1.new B(); // 4
used, So new B() is used twice. And InnerCounter incremented twice.
 
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Hi GaneshKumar,

new A().new B(); // both constructor run here so you will get A0B0
A a1 = new A(); // Here only one constructor works and incremented name as A1 but not invoked.
a1.new B(); // only B constructor runs, so you get A1B1 and A constructor wont run here again since B only uses the refernce
a1.new B(); // same as previous only B works and so A1B2

Hope this clear you.

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