We’re being asked to** calculate the Avogadro's number using the radius, density and formula weight of Pd metal**

Recall that Avogadro's number is given by:

$\overline{){{\mathbf{N}}}_{{\mathbf{A}}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{number}\mathbf{}\mathbf{of}\mathbf{}\mathbf{atoms}}{\mathbf{1}\mathbf{}\mathbf{mol}}}$

In this case, we have to find the number of atoms in an FCC crystal and the number of moles present using the provided data

A **face-centered cubic lattice**** contains an atom in each of the face of the cube and an atom in each of the corners****.** It looks like this:

Pd crystallizes with a face-centered cubic unit cell. It has a density of 6.00 g/cm^{3} and a radius of 138 pm and a FW of 106.42 g/mol. Use these data to estimate Avagadro’s number.

A. 6.0 x 10^{23}

B. 5.9 x 10^{23}

C. 3.1 x 10^{23}

D. 11.9 x 10^{23}

E. 6.0 x 10^{24}

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Unit Cell concept. You can view video lessons to learn Unit Cell. Or if you need more Unit Cell practice, you can also practice Unit Cell practice problems.

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