Run servlet program when start apache-tomcat

[R Sugan]

Hi,

I tried to get output of my Servlet program when start Apache-tomcat.How to proceed this process.please assist to me.


Thanks

[Surya Kant]

You can do it by specifying
<load-on-startup> in servlet definition.
You can find this in web.xml

[Bauke Scholtz]

You can't get response without firing a request.

Besides, this is a design smell. Have you considered ServletContextListener?

[Bear Bibeault]

Since the purpose of a servlet is to render a response to a request, and there's no request to respond to on startup, it makes no sense to do this with a servlet. Investigate the use of listeners as Bauke recommended.

[R Sugan]

Hi,

Thanks for reply.I got the output.