Switch case with static variable

[Jahnvi Pathak]

Hi,

Please read the code given below.

public class FlowControl1 {

final static short x = 2;
final static int y = 0;

public static void main(String[] args) {
for(int z=0; z<4; z++){
switch(z){
case x: System.out.print("0 ");
case x-1: System.out.print("1 "); break;
default: System.out.print("def ");
case x-2: System.out.print("2 ");
}
}

}

}


Output is : 2 1 0 1 def 2

My question is when z = 2, at that time it will go to "case x" as x = 2, but it also goes to the condition "case x-1". I think it should not be. Because "case x-1" will result in 1 and z is not equals to 1. But both code and output is correct. Can anybody please help me?

Thanks.

-Jahnvi

[fred rosenberger]

if you don't have a 'break' statement, all the code in all subsequent cases execute.

try reversing the order of your "case x" and "case x-1" and see what happens...

[Shin Kudo]

switch only does comparison once to find the matching case. It does not compare with other cases when it "falls through".

[Jahnvi Pathak]

Thanks to both of you Fred and Shin.

This is the very simple rule. I wonder how could I miss it!!

Well, once again thanks.

- Jahnvi