Set problem

[sweety sinha]

Map s = new HashMap();
			s.put("ram","1");
			s.put("ram","2");
			s.put("ram2","3");
			s.put("ram","4");
			s.put("ram2","5");
			System.out.println(s);
			System.out.println(s.size());

when this code runs print
ram2=5 ram=4
and size 2 but here no hashCode is used so it should print size 5

please help

thanks in advance

[Joshua Ebarvia]

sweety sinha wrote:

Map s = new HashMap();
			s.put("ram","1");
			s.put("ram","2");
			s.put("ram2","3");
			s.put("ram","4");
			s.put("ram2","5");
			System.out.println(s);
			System.out.println(s.size());

when this code runs print
ram2=5 ram=4
and size 2 but here no hashCode is used so it should print size 5

please help

thanks in advance

Hi.

Hashmap doesnt accept duplicate keys. So your hashmap s would only have 2 because you only have two keys "ram" and "ram2".
The other put operation wasn't successful because it has duplicate keys. By the way I think if it is not successful in putting it to the hashmap it will return false.

[Ankit Garg]

here no hashCode is used so it should print size 5

You are using String as keys and the String class has an implementation of equals and hashCode method which will be used by the HashMap...

[sweety sinha]

thanks Ankit & Joshua Ebarvia for quick response