How many Objects will create

[krishna Mohan Athota]

Hi friends,

How many objects will create when following simple program executed:

public class ObjectsCount{

	ObjectsCount []ob;

	public ObjectsCount(ObjectsCount... ob){
		this.ob = ob;
	}

	public static void main(String... args){
		ObjectsCount obc = new ObjectsCount(new ObjectsCount[] {new ObjectsCount(), new ObjectsCount()});
	}

}

I beleive total of 4 objects will create :
1. three "ObjectsCount" objects and one "2-dimensional array".

Am i correct?

[Ankit Garg]

Yes you are correct. Also please Use Code Tags when you post a source code. Edit your message using button and then add code tags to it...

[Valentin Ivanov]

 new ObjectsCount()

???

[Ankit Garg]

Valentin Ivanov wrote:

 new ObjectsCount()

???

What is this , are you confused what ObjectsCount is??

[Valentin Ivanov]

I'm wondering is new ObjectsCount() matching the constructor signature?

[Ankit Garg]

Valentin Ivanov wrote:I'm wondering is new ObjectsCount() matching the constructor signature?

The constructor takes a var-arg of ObjectsCount objects. Since it is a var-arg method, so you can pass zero or more arguments to it.

PS: If the constructor was overloaded, and there was a no-arg constructor available, then that constructor would've been called as you can see in this thread...

[Valentin Ivanov]

Yeah , you are right, no doubt.
But i was thinking if the Var Args elements are used in the method and at some moment you call that method with no arguments... will this raise runtime exception?

[Ankit Garg]

Valentin Ivanov wrote:But i was thinking if the Var Args elements are used in the method and at some moment you call that method with no arguments... will this raise runtime exception?

No, no runtime exception or compile time error...

[Ninad Kulkarni]

Valentin Ivanov wrote:Yeah , you are right, no doubt.
But i was thinking if the Var Args elements are used in the method and at some moment you call that method with no arguments... will this raise runtime exception?

Valentin See The code below.

public class ObjectsCount{

	ObjectsCount []ob;

	public ObjectsCount(ObjectsCount... ob){
		this.ob = ob;
	}

	public static void main(String... args){
		ObjectsCount obc = new ObjectsCount(new ObjectsCount[] {new ObjectsCount(), new ObjectsCount()});
		obc.doIt();
		obc.doIt(new String[]{ "1", "2" });
	}
	public void doIt(String... strArr) {
		System.out.println(strArr.length);
//		System.out.println(strArr[0]);
	}

}

Output is

0
2

If you remove comment on line number 16 then it will throw runtime exception because its zero length array.

[Valentin Ivanov]

That's what I was thinkig about. Thanks
All is clear