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Overriding the start method of Thread Class

 
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What happens in the above code ?? I m not able to understand the fact of overriding the start() method of the thread class and still get an output of MyThread: start() followed by MyRunnable:run() Please can some one explain thank you
 
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Dhruv Arya wrote:
What happens in the above code ?? I m not able to understand the fact of overriding the start() method of the thread class and still get an output of MyThread: start() followed by MyRunnable:run() Please can some one explain thank you



When you call, myThread.start(), you will get the "MyThread:start()" message.

When you call, thread.start(), the new thread will call the run() method of your runnable, and you will get the "MyRunnable:run()" message.

Henry
 
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Runnable interface has only one method, public void run(). Even if the runnable object has a public void start() method, it doesn't get into picture. But the if Thread object has a public void start() it does come into picture and affect how thread is submitted for run.
 
Dhruv Arya
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Thanks Alot I totally get my mistake you guys made my day Thank You
 
Don't get me started about those stupid light bulbs.
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