var-args

[Raju Champaklal]

  
 public class DeclareStuff  {
 
	public static void main(String[] args) {
	int[] a={1,2,3};
            m(new Integer[]{1,2,3});
	}
        static void m(Object... o){System.out.println(o[0]);}


 }
  

this prints 1 whereas

  
 public class DeclareStuff  {
 
	public static void main(String[] args) {
	int[] a={1,2,3};
            m(new int[]{1,2,3});
	}
        static void m(Object... o){System.out.println(o[0]);}


 }
  

this prints some absurd value..why? isnt int boxed to integer here?

[Neha Daga]

because second time you are passing an object(primitive int array) not an array of objects(class Integer) so, I think its giving you the address of the int[] object but when you pass Integer[] object you have a new integer at every index and the class' tostring method returns the value hold in the object.

[Raju Champaklal]

Thanks Neha...that was superb

[Raju Champaklal]

    
 public class DeclareStuff  {
 
	public static void main(String[] args) {
	int[] a={1,2,3};
            m(new Integer[]{1,2,3});// warning
	}
        static void m(Object... o){System.out.println(o[0]);}


 }
    

and why do i get a warning here? but not when i use static void m(Object[] o) ?

  
 public class DeclareStuff  {
 
	public static void main(String[] args) {
            
	
            m(new Integer[]{1,2,3});
	}
        static void m(Object... o){System.out.println(( o)[1]);}
 static void m(Object o){System.out.println("c");}

 }
  

and here i thught the output to be c because according to a rule var-args are chosen if no option is left....but output is 1

is this becasue of being specific...that is Object... is more specific than Object afterall Object... is an Object[] and we are passing an Integer[] /???/ too much confusion....