how to invoke the first superclass constructer with out invoking the subclass constructer..?

[santhosh.R gowda]

Dear All

The program discription :_

class A
{
    A()
  {

  }
}

class B extends A
{
    B()
   {
    
    }

}

class C extends B
{
    C()
  {
     // if i write super() it will invoke B default constructer  
  }
}

 

Kindly tell me the statement to invoke A default constructer from c default constructer with out using executing B default constructer

[Wouter Oet]

You can't. this() and super() can only be called from a constructor context. And you can't do super().super() or something like that. Only the super class is visible. If you just want an A object then just directly call the constructor.

[Seetharaman Venkatasamy]

Not Possible. You cant break the Constructor Chaining.

[Seetharaman Venkatasamy]

Wouter win the race!

[santhosh.R gowda]

Thanks a lot....

[salvin francis]

Let me "try" to explain why ....
ahem

C extends B and B extends A

So, if you want to create an Object of C, A has to be created *, or a better word would be .. Constructed.
Next, B will be constructed and then C.

Thus the constructors will be called in that order.
You can choose to call a specific Immediate parent constructor by using super keyword

However skipping B's constructor would mean that C will be created without B and thus will not work.

* Note that only one object is created not 3

[Campbell Ritchie]

Better to say that part of the C object which is unchanged from A is created, then that part unchanged from B, but not in A, then the parts only in C.