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Replacing an Interceptor in the Default Stack

 
Greenhorn
Posts: 24
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Hi all,

I have created my own workflow interceptor which I would like to replace the default workfloaw interceptor for some actions. I would like to define my own stack to be the same as the default stack but with my custom workflow interceptor in place.

I have done it the manual way. i.e:

<interceptors >
<interceptor name="dynamicInputWorkflow" class="one.of.my.packages.DynamicInputWorkflowInterceptor"/>
<interceptor-stack name="dynamicInputWorkflowStack" >
<interceptor-ref name="exception"/>
<interceptor-ref name="alias"/>
<interceptor-ref name="servletConfig"/>
<interceptor-ref name="i18n"/>
<interceptor-ref name="prepare"/>
<interceptor-ref name="chain"/>
<interceptor-ref name="debugging"/>
<interceptor-ref name="profiling"/>
<interceptor-ref name="scopedModelDriven"/>
<interceptor-ref name="modelDriven"/>
<interceptor-ref name="fileUpload"/>
<interceptor-ref name="checkbox"/>
<interceptor-ref name="staticParams"/>
<interceptor-ref name="actionMappingParams"/>
<interceptor-ref name="params">
<param name="excludeParams">dojo\..*,^struts\..*</param>
</interceptor-ref>
<interceptor-ref name="conversionError"/>
<interceptor-ref name="validation">
<param name="excludeMethods">input,back,cancel,browse</param>
</interceptor-ref>
<interceptor-ref name="dynamicInputWorkflow">
<param name="excludeMethods">input,back,cancel,browse</param>
</interceptor-ref>
</interceptor-stack>
</interceptors>

Is it possible to define a custom stack to use default stack and replace workflow interceptor with my own custom workflow interceptor without having to manually copy and paste the whole default interceptor stack?

Thanks for your help. Kind regards,

James
 
Author
Posts: 12617
IntelliJ IDE Ruby
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No, although most stacks I've made have been composed of groups of other interceptors.

There is no way to "inject" an interceptor into a collection of others (nor should there be, in my opinion; too much possibility of abuse).
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