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Try Catch Block

 
Ranch Hand
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In try catch block
try{}
catch(Exception e)
{}
catch(SQLException e)
{}

If Sql exception occurs which catch block gets execute.
 
Sheriff
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The main question is : does it compile ? Did you try it ?
 
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Hi Rajendra,

Just try to compile the above code... you will get the answer...

 
Rajendra Prakash
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Ya i tried . It throws " exception java.sql.exception has already been caught. If sqlexception caught in catch(Exception e) block then why catch(sqlexception)
 
Christophe Verré
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It throws " exception java.sql.exception has already been caught.


No, it doesn't throw anything. It's a compile error.

If sqlexception caught in catch(Exception e) block then why catch(sqlexception)


SQLException extends Exception, so if you catch Exception first, you'll never be able to reach the SQLException catch block. However, if you place the SQLException catch block before the Exception one, you'll be able to catch SQLException specifically, and catch all other Exceptions in the other catch block. You always have to write multiple catch blocks from most specific, to most general.
 
Greenhorn
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yes, not only for SQLException, but for any exception, this holds true. The catch(Exception e) must be last in the series of catch blocks that you might have.
 
Ranch Hand
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yes ... Exception is the big daddy ... the master which can catch any other exception as all the exceptions extends Exception
 
Sheriff
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There are actually two things you can catch after Exception: Error and Throwable. But again, Error must be caught* before Throwable.

* Actually, catching any Error is usually a bad idea. They are errors because usually they are really unrecoverable.
 
Marshal
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Deepak Mahalingam wrote: . . . catch(Exception e) must be last in the series of catch blocks that you might have.

Unless you are brave enough to use catch(Throwable), which is hardly ever necessary.
 
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