this below gives 192.168.10.2 well in which case this gives 127.0.0.1

[Leonidas Savvides]

DatagramPacket receivePacket = new DatagramPacket( data, data.length );

[b]receivePacket.getAddress()[/b] //this below gives [b]192.168.10.2[/b] well, App run localhost and this is a local Lan ip, well in which case this gives [b]127.0.0.1[/b] ???

            displayMessage( "\nPacket received:" + 
               "\nFrom host: " + receivePacket.getAddress() + 
               "\nHost port: " + receivePacket.getPort() + 
               "\nLength: " + receivePacket.getLength() + 
               "\nContaining:\n\t" + new String( receivePacket.getData(), 
                  0, receivePacket.getLength() ) );

[Nitesh Kant]

Your question is really not clear. It will be nice if you can explain more about your problem.

[Leonidas Savvides]

receivePacket.getAddress() //this below gives 192.168.10.2 well, App run localhost and this is a local Lan ip, well in which case this gives 127.0.0.1 and which case give as given as tried: 192.168.10.2 ? ???

[Carol Enderlin]

I see question marks, but do not see a question.

[Leonidas Savvides]

when we get 127.0.0.1 and when 192.168.10.2 (my PC address in LAN) ?