How to convert string to xml file in java

[vijayakumar durai]

Hi friends
I am getting the response from webservice as string below content .can anyboy tell how to convert string to xml file in java

   

<?xml version="1.0" encoding="utf-8"?><soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><soap:Body><LoginResponse xmlns="http://tempuri.org/QuestIPhoneWebService/QuestIPhoneWebService"><LoginResult><RETURN_VALUE><ERROR RESULT= '-1' DESC = 'The password entered into the system is not valid. Please check your password and try again.'/></RETURN_VALUE></LoginResult></LoginResponse></soap:Body></soap:Envelope>

 

Thanks in advance

[pawan chopra]

Try this one :

 
            import java.io.File;
import java.io.IOException;
import java.io.StringReader;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.transform.Result;
import javax.xml.transform.Source;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;

import org.w3c.dom.Document;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;

public class StringToXML {
    public static void main(String[] args) {
        String xmlString = "<?xml version=\"1.0\" encoding=\"utf-8\"?><soap:Envelope xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\"></soap:Envelope>";

        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();

        DocumentBuilder builder;
        try
        {
            builder = factory.newDocumentBuilder();

            // Use String reader
            Document document = builder.parse( new InputSource(
                    new StringReader( xmlString ) ) );

            TransformerFactory tranFactory = TransformerFactory.newInstance();
            Transformer aTransformer = tranFactory.newTransformer();
            Source src = new DOMSource( document );
            Result dest = new StreamResult( new File( "xmlFileName.xml" ) );
            aTransformer.transform( src, dest );
        } catch (Exception e)
        {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }
}


  

[Booma Devi]

[code=java]Hi,

Can any one please solve this problem?

I have one xml file called books.xml and is having the following contents..

<?xml version="1.0" encoding="UTF-8" standalone="no" ?> 
- <message type="Book">
  <source>Hello</source> 
    </message>

Now, I need to append the Nodes to the books.xml file. How can I do this?

I have done the below code in java.. But my code is inserting the string to existing books.xml file... Not inserting as XML contents..

                                           [code=java]    String xmlString="<message type=\"CAR\"><target>DES</target></message>";
			DocumentBuilderFactory dbf=DocumentBuilderFactory.newInstance();
			DocumentBuilder db =dbf.newDocumentBuilder();

			// Read books.xml file
			Document dct=db.parse("C:\\Data\\Books.xml");
			Element root = dct.getDocumentElement();
			Text text1 = dct.createTextNode(xmlString)	==========> HOw can this convert to XML string...		
			root.appendChild(text1);
			// Create blank document
			Document mainDoc = db.newDocument(); 
			Element root1 = mainDoc.createElement("Root1");  
			mainDoc.appendChild(root1);
			// Copy the existing XML file with newly created element
			root1.appendChild(mainDoc.importNode(root, true));  
               		               // Save the created DOM tree to LBN.XML file...
			Transformer transformer = TransformerFactory.newInstance().newTransformer();
			transformer.setOutputProperty(OutputKeys.INDENT, "yes");
			StreamResult result = new StreamResult(new FileWriter("C:\\Data\\RT.xml"));
			DOMSource source = new DOMSource(mainDoc);
			transformer.transform(source, result);
			System.out.println("File saved!");
                               //	Save the modified DOM tree to books.XML file...
			Transformer transformer1 = TransformerFactory.newInstance().newTransformer();
			transformer.setOutputProperty(OutputKeys.INDENT, "yes");
			StreamResult result1 = new StreamResult(new FileWriter("C:\\Data\\books.xml"));
			DOMSource source1 = new DOMSource(dct);
			transformer1.transform(source1, result1);

}

I am geeting the output looks like below:

<?xml version="1.0" encoding="UTF-8" standalone="no" ?> 
- <Root1>
- <message type="Book">
  <source>Hello</source> 
    </message>
  <message type="CAR"><target>DES</target></message> ===========> Needs to convert this to XML...
  </gid_message>
  </Root1>

Exact output should like as below..

- <Root1>
- <message type="Book">
  <source>Hello</source> 
    </message>
   </message type>
- <message type="CAR">
<Target>DES</Target>  
   </message type>

  </Root1>

[/code][/code]

[Saral Saxena]

pawan chopra wrote:Try this one :

 
            import java.io.File;
import java.io.IOException;
import java.io.StringReader;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.transform.Result;
import javax.xml.transform.Source;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;

import org.w3c.dom.Document;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;

public class StringToXML {
    public static void main(String[] args) {
        String xmlString = "<?xml version=\"1.0\" encoding=\"utf-8\"?><soap:Envelope xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\"></soap:Envelope>";

        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();

        DocumentBuilder builder;
        try
        {
            builder = factory.newDocumentBuilder();

            // Use String reader
            Document document = builder.parse( new InputSource(
                    new StringReader( xmlString ) ) );

            TransformerFactory tranFactory = TransformerFactory.newInstance();
            Transformer aTransformer = tranFactory.newTransformer();
            Source src = new DOMSource( document );
            Result dest = new StreamResult( new File( "xmlFileName.xml" ) );
            aTransformer.transform( src, dest );
        } catch (Exception e)
        {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }
}


  

In which drive(C) or drrive (D), it will save the xmlFileName.xml, where you have mentioned that..?

[Booma Devi]

Hi,

I have tried the code which you have suggested... My question is, after converting the xml string to XML file say A.xml...

I want to read the A.XML file and append the data (data is in xml string) to the A.XML file...

[Booma Devi]

I have stored the xml file ( xmlfilename.xml) in different name (I have changed the xml file xmlfilename.xml to books.xml) in my program...

Now, I have another string which contains the XML tags needs to be appended to the existing file books.xml file..

Thanks in Advance...

[Booma Devi]

Hi Saral,

Thanks for your response.. I have found the solution...

	String XMLString = "<College><Dept>CSE</Dept></College>";
		DocumentBuilderFactory dbf=DocumentBuilderFactory.newInstance();
		DocumentBuilder db =dbf.newDocumentBuilder();
		// Read College.xml file
		Document dct=db.parse("College.xml");
		Element root = dct.getDocumentElement();
		Document document = db.parse( new InputSource(   
				new StringReader(XMLString))); 
		Element root2=document.getDocumentElement();
		Document mainDoc = db.newDocument(); 
		Element root1 = mainDoc.createElement("Root1");  
		mainDoc.appendChild(root1);
		// Copy the existing XML file with newly created element
		root1.appendChild(mainDoc.importNode(root, true));  
		root1.appendChild(mainDoc.importNode(root2,true));
		Transformer transformer = TransformerFactory.newInstance().newTransformer();
		transformer.setOutputProperty(OutputKeys.INDENT, "yes");
		StreamResult result = new StreamResult(new FileWriter("NewAppendedXMLFile.xml");
		DOMSource source = new DOMSource(mainDoc);
		transformer.transform(source, result);
		System.out.println("File saved!");
		}
	}

Here is the output:                                                                                   

College.Xml:                                                                                            

 <?xml version="1.0" encoding="UTF-8" standalone="no" ?>                                                           
   <Dept>EEE</Dept>
   </College>

NewAppendedXMLFile.xml:
<?xml version="1.0" encoding="UTF-8" standalone="no" ?> 
- <Root1>
- <College>
   <Dept>CSE</Dept>
   </College>
- <College>
   <Dept>EEE</Dept>
   </College>
   </Root1>

[Saral Saxena]

Rt thava wrote:
Hi Saral,

Thanks for your response.. I have found the solution...

	String XMLString = "<College><Dept>CSE</Dept></College>";
		DocumentBuilderFactory dbf=DocumentBuilderFactory.newInstance();
		DocumentBuilder db =dbf.newDocumentBuilder();
		// Read College.xml file
		Document dct=db.parse("College.xml");
		Element root = dct.getDocumentElement();
		Document document = db.parse( new InputSource(   
				new StringReader(XMLString))); 
		Element root2=document.getDocumentElement();
		Document mainDoc = db.newDocument(); 
		Element root1 = mainDoc.createElement("Root1");  
		mainDoc.appendChild(root1);
		// Copy the existing XML file with newly created element
		root1.appendChild(mainDoc.importNode(root, true));  
		root1.appendChild(mainDoc.importNode(root2,true));
		Transformer transformer = TransformerFactory.newInstance().newTransformer();
		transformer.setOutputProperty(OutputKeys.INDENT, "yes");
		StreamResult result = new StreamResult(new FileWriter("NewAppendedXMLFile.xml");
		DOMSource source = new DOMSource(mainDoc);
		transformer.transform(source, result);
		System.out.println("File saved!");
		}
	}

Here is the output:                                                                                   

College.Xml:                                                                                            

 <?xml version="1.0" encoding="UTF-8" standalone="no" ?>                                                           
   <Dept>EEE</Dept>
   </College>

NewAppendedXMLFile.xml:
<?xml version="1.0" encoding="UTF-8" standalone="no" ?> 
- <Root1>
- <College>
   <Dept>CSE</Dept>
   </College>
- <College>
   <Dept>EEE</Dept>
   </College>
   </Root1>

HI Rt thava ,

Can you please post your final code here so that we can have a look because one thing that is not clear is that where you have mentioned the path in the code from where it will pick up the college.xml....just like that ...

 File fXmlFile = new File("c:\\college.xml");
		DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();

and where you have mentioned the path of the final xml that is created in which drive and under which directory..!!

It will be graet if you can post your full and final solution that will be a great help..!! thanks in advance..!!

[John Jai]

Saral Saxena wrote:
Can you please post your final code here so that we can have a look because one thing that is not clear is that where you have mentioned the path in the code from where it will pick up the college.xml....just like that ... ...and where you have mentioned the path of the final xml that is created in which drive and under which directory..!!

The path if not specified will take the folder from where the execution is done. Try below code in your desktop.

public static void main(String...args){
	File f1 = new File("SomeFile.txt");
	System.out.println(f1.getAbsolutePath());
		
	File f2 = new File("NewFile.txt");
	try {
		boolean b = f2.createNewFile();
		if(b){
			System.out.println("File created -> " + f2.getAbsolutePath());
		}else {
			System.out.println("File might already exists..");
		}
	} catch (IOException e){
		e.printStackTrace();
	}		
}

[Booma Devi]

Hi John,

Thanks for your response.. Here is my final code..

                                public class XMLFinal {
	                 public static void main(String[] args)throws IOException {
     	                 String xmlString="<College><Dept>EEE</Dept></College>";
		 DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();   
		DocumentBuilder builder; 
		builder = factory.newDocumentBuilder(); 
		Document document = builder.parse( new InputSource(new StringReader(xmlString))); 
   	                TransformerFactory tranFactory = TransformerFactory.newInstance();   
	                Transformer aTransformer = tranFactory.newTransformer();   
		Source src = new DOMSource( document );   
		Result dest = new StreamResult( new File( "C:\\Data\\college.xml" ) );   
		aTransformer.transform(src,dest );  
                                System.out.println("File Saved!!!!!!");
		}
}

           public class MainXML
                  {	public static void main(String args[])throws Exception,DOMException
	  {      
	       String XMLString = "<College><Dept>CSE</Dept></College>";   
	        DocumentBuilderFactory dbf=DocumentBuilderFactory.newInstance();   
	        DocumentBuilder db =dbf.newDocumentBuilder();   
	        // Read College.xml file   
	        Document dct=db.parse("C:\\Data\\college.xml");   
	        Element root = dct.getDocumentElement();   
	        Document document = db.parse( new InputSource(new StringReader(XMLString)));    
	        Element root2=document.getDocumentElement();   
	        Document mainDoc = db.newDocument();    
	        Element root1 = mainDoc.createElement("Root1");     
	        mainDoc.appendChild(root1);   
	        // Copy the existing XML file with newly created element   
	        root1.appendChild(mainDoc.importNode(root, true));     
	        root1.appendChild(mainDoc.importNode(root2,true));   
	        Transformer transformer = TransformerFactory.newInstance().newTransformer();   
	        transformer.setOutputProperty(OutputKeys.INDENT, "yes");   
	        StreamResult result = new StreamResult(new FileWriter("C:\\Data\\NewAppendedXMLFile.xml"));   
	        DOMSource source = new DOMSource(mainDoc);   
	        transformer.transform(source, result);   
	        System.out.println("File saved!");   
	        }   
	    }  

[Jesper de Jong]

If you have the XML in a string, and you want it in a file, then the only thing you have to do is save the string into a file. No need to use the XML parsing API.

public static void main(String[] args) throws IOException {
    String xmlString = "<?xml version=\"1.0\" encoding=\"utf-8\"?><soap:Envelope " +
            "xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\" " +
            "xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" " +
            "xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\"></soap:Envelope>";

    FileWriter out = new FileWriter("A.xml");
    out.write(xmlString);
    out.close();
}

[Booma Devi]

Thanks jespar.. :-)

[Chathu Dan]

Hopefully you will find the answer here

Create XML using Java DOM

<?xml version="1.0" encoding="UTF-8" ?>
 <order>
 <orderDetails>
  <waiterName>Siridasa</waiterName>
  <kitchName>Chines Kitchen</kitchName>
  <tableName>20</tableName>
  </orderDetails>
<item>
  <itemid>ARR01</itemid>
  <itemName>DCL White Arak</itemName>
  <itemQty>1</itemQty>
  </item>
 <item>
  <itemid>ARR02</itemid>
  <itemName>Lemon Gin</itemName>
  <itemQty>2</itemQty>
  </item>
 <item>
  <itemid>ARR03</itemid>
  <itemName>Ritz</itemName>
  <itemQty>10</itemQty>
  </item>
  </order>

you can find the java source code here Create XML using Java DOM

[Paul Clapham]

Arulmozhi Govindaraju,
Your post was moved to a new topic.
Please start a new thread when your question isn't an answer to the thread you considered posting to.

[jhessica valdez]

try this code..

import java.io.*;
import javax.xml.parsers.*;
import org.w3c.dom.*;
import org.xml.sax.*;

public class Util {

public static Document stringToDom(String xmlSource)
throws SAXException, ParserConfigurationException, IOException {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
return builder.parse(new InputSource(new StringReader(xmlSource)));
}
}