Assigning double dimension array to single dimension array of type Object

[ankur trapasiya]

public class ID
{
public static void main(String... args)
{
Object [] object = new String[5][5];
int counter=0;
for (Object o : object )
{
counter++;
}
System.out.println(counter);
}
}


this code outputs 5 ...
I am not getting why ...
can anyone explain ??? please ..

[Kushan Athukorala]

Hi Ankur,

Can you tell us what you understand from this code first?

Then we can help you to figure out where you go wrong.

Thanks,
Kushan

[Mohamed Sanaulla]

Head First Java has beautifully explained this Array concept. I would recommend you to read that book if you have a copy of it. Its worth reading for a beginner.

Also please UseCodeTags to post your source code.

[Matthew Brown]

Hint: remember that a two-dimensional array is really an array of arrays.

[ankur trapasiya]

hey guys..... my doubt got cleared thankss...

[Kushan Athukorala]

Appreciate your courage

Regards,
Kushan

[Rahul Saple]

Could someone please tell me what exactly is going on behind the scenes. I understand that a two dimensional string array is created and the reference value of that 2-D array is given to a one dimensional Object array reference.
But how is it possible? By that rule the following line of code should compile

Number[] = new Integer[6][6]; 

But it doesn't. Is it because in Java every Array is an Object? Can anyone shed more light on this?

[Matthew Brown]

Rahul Saple wrote:Is it because in Java every Array is an Object?

2D array = array of arrays = array of Objects

[Rahul Saple]

I knew I was on to something. So close .Thanks.

[Ilakya Mukunth]

int[][] a = {{1,2},{0,1,2},{-1,0,2}}; // 1
Object[] obj = (Object[])a.clone(); // 2
int [] obj1 = (int[])a.clone(); //3
The line 1 and 2 compiles fine. If I add line-3, it does not run. Can anyone explain me why?