Superclass Constructor

[karl czukoski]

Given:

class Building
{
  Building() 
  { 
  System.out.print("b "); 
  }
  Building (String name)
  {
    this.();    
    System.out.println("hn " + name);
   }
}

public class House extends Building
{
  House() 
  { 
    System.out.println("h "); 
  }
  House (String name)
  {
     this();   System.out.print("bn " + name);
  }


  public static void main(String[] args)
  {
    new House ("x ");
  }
}

prints: b h hn x

Can someone explain why the first constructor Building() of the superclass Building is called instead of the second constructor Building(String name) ?

[Tom Reilly]

After I fixed the compiler error, it does not print b h hn x . It prints:
b h
bn x
I think you are running old code.

[Prasad Kharkar]

@ karl
welcome to the javaranch family

please QuoteYourSources

[karl czukoski]

Thanks Prasad

So correct me if wrong but I think the first constructor Building() of the superclass Building is used b/c the compiler looks for the no-arg constructor (basing this logic off of question 2 pg. 172 explanation).

[Prasad Kharkar]

QuoteYourSources means please provide the source from where you got this question