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How to pick up the servlet in the URL

 
Greenhorn
Posts: 4
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Hi all, newbie again here.......

Just followed a simple excercise of how to implement a servlet. Up until this point there has been no mention of using a web.xml file!

So far I have compiled a java bit of code into a .class and placed it in my directory webapps/ch01/WEB-INF/classes as advised. The code looks like this:


import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class ch01_06 extends HttpServlet
{
public void doGet(HttpServletRequest request,
HttpServletResponse response)
throws IOException, ServletException
{
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<HTML>");
out.println("<HEAD>");
out.println("<TITLE>");
out.println("A Web Page");
out.println("</TITLE>");
out.println("</HEAD>");
out.println("Hello there!");
out.println("</BODY>");
out.println("</HTML>");
}
}


Now the only instructions it then gives me is to use the url: http://localhost:8080/ch01/servlet/ch01_06

I then get the dreaded message this resource is not available 404 etc etc

As I have no web.xml file within my webapps folder, I am confused as to what I have to do for my servlet to be dispalyed in the browser. The instructions in the book have been quite clear up until now, can someone help?

Thanks

 
Sheriff
Posts: 67694
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Your tutorial is either very old, very poor, or both.

  • Servlets must be placed in a package other than the default.
  • The package hierarchy needs to reside at WEB-INF/classes, not WEB-INF.
  • You must declare and map the servelt in the deployment descriptor (web.xml).


  • I'd highly recommend finding a better and more modern tutorial.

     
    Ranch Hand
    Posts: 165
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    I can highly recommend the following books which have helped my understanding massively.

    Head First Java
    Head First Java Servlets and JSP
     
    Don't get me started about those stupid light bulbs.
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