Nested if()

[Anu satya]

HI all, I have a strange requirement:

if(condition1){
   if(condition2){
       if(condition3) {
       ...........
        ..............
         }
   }
}else{
  ................
   ...............
   }

My requirement is:
if (condition3) is false, then go to 'else' part given in the above code sample. Above code sample is the existing structure. condition3 is the new enhancement. I can't change the existing code.

Is it possible to achieve this? If not, is there any other way? please suggest.

[fred rosenberger]

if you CAN'T change the existing code AT ALL....The only way I see to do it is something like:

if(condition1){  
   if(condition2){  
      if(condition3) {  
      ...........  
       ..............  
      }  
      else {
          //copy the code in the else block below to here
      }
   }  
}else{  
  ................  
   ...............  
}  

[Maneesh Godbole]

I am having serious trouble understanding how a fix can be put into place without changing the code.

[Campbell Ritchie]

Please confirm there are no } and { which you have hidden behind the ......... because an else refers to the if whose block is completed by the } immediately preceding the else. If Maneesh and Fred don't think it can be done, I know there is no point somebody else trying

[Anu satya]

Campbell Ritchie wrote:Please confirm there are no } and { which you have hidden behind the ......... because an else refers to the if whose block is completed by the } immediately preceding the else. If Maneesh and Fred don't think it can be done, I know there is no point somebody else trying

Thanks all for your reply. My problem is :
1) Is it possible to go to outer Most Else if inner most if() condition is false !
2) If I can change the above code, how can i fix the issue ?

Please help.

[Paul Clapham]

If you want to call the same code from two different places in your if-then-else tree, then put that code into a method and call that method in the two places.

[Anu satya]

Thanks Paul.
Is there any other solution other than calling the method from two different places?

[fred rosenberger]

Java does not have a way to break out of an inner-nested if to the outer else. that really violates the idea of what a if-statement does. You are basically saying

if (Some of the time when part 1 is true, but we don't really know which of those times)
   do A
else
   do B

The correct way to do it is to either

a) extract the common code to a method and call it from the two places
b) re-write your logic to something like

if (condition1 or !condition3)
{
  if (condition2)
  {
     //do something
  }
}
else
{
   //do something else
}  

Note: I have not verified the above is the correct logic...I don't have time to make out a truth table.

[Paul Clapham]

Anu satya wrote:Is there any other solution other than calling the method from two different places?

You could possibly reorganize the if's and else's so that the code only needed to be in one place. However since you don't have a real example of this, just made-up things, anything is possible but nothing can be done.