strange behavior of overridden call

[naveen yadav]

Hi ranchers ,

public class Greek{

     int i=1;

     public int getI(){
          System.out.print("Super");
          return i;
     }

     public static void main(String arhs[]){
         
                  Greek ga=new Arabik();
          
		  System.out.println(ga.i+" , "+ga.getI()); 
     }
}

class Arabik extends Greek{

     int i=2;

     public int getI(){
          System.out.print("Sub");
          return i;
     }

}

The output is :
sub1, 2

In line 14 i is printed and then getI() is called. and expected output is : 1, Sub2

But when i execute the code getI() is called and then i is printed and output is (Unexpected) : Sub1, 2

Why call is made before i is printed ??

[sakthi moorthy]

Hi Naveen Yadav,

 System.out.println(ga.i+" , "+ga.getI());   // line 1 

In Above Code, First Precedence goes to the "ga.getI()" as () operator has higher precedence, so it will call the getI() method of Arabik before printing anything,
1) we have

System.out.print("Sub");

in getI() method of Arabik which will print "Sub" First
2) later above code i.e., line 1 starts print the content from left to right as + operator has left to right associativity, so ga.i will print the value of "1" , because you can't override the instance variable in inheritance.
3) Then It prints ","
4) Then returned value of ga.getI() method of Arabik, which is "2"


so you are getting Sub1 , 2

Please correct me if i am wrong anywhere and i am much interested to see how other people are thinking and describing the answer, which will help us to understand more about the topic

Thanks & Regards
S.Sathiya

[Nomaan Butt]

quite right,
we can say instance variables of the super class get hidden in the subclass. we can access them through the super class which is happing in the above code and also your precedence explanation is right i believe.