Exception

[Ahmed Kotb]

Hi All,

When trying to extract ZIP file , encountered the following Exception [java.util.zip.ZipException : invalid block type]

Can anyone help please?

[Hebert Coelho]

I believe your file is corrupted.

[Ahmed Kotb]

no File is not corrupted , i tried to extract it with winrare and it is extracted successfully

[Henry Wong]

Ahmed Kotb wrote:no File is not corrupted , i tried to extract it with winrare and it is extracted successfully

WinRar supports many many different formats -- including the copyrighted rar format. If the cause is because you are using a format that isn't support, I don't know what to tell you.

Henry

[Ahmed Kotb]

to be with me this is the code i use

public String unZip(String zipFileName, String configPath) {
        final int BUFFER = 2048;
        String reqNam = "";
        try {
            LogsModel.log(c,"System","started in extraction operation of required ZIP file: ["+zipFileName+"].");
            BufferedOutputStream dest = null;
            FileInputStream fis = new FileInputStream(zipFileName);
            ZipInputStream zis = new ZipInputStream(new BufferedInputStream(fis));
            ZipEntry entry;
            while ((entry = zis.getNextEntry()) != null) {
                String FiNa = entry.getName();
                String FileExt = FiNa.substring(FiNa.lastIndexOf("."), FiNa.length());
                reqNam = providerName + NowDate + FileExt;
                LogsModel.log(c,"System","now extracting ZIP file: ["+entry.getName()+"].");
                int count;
                byte data[] = new byte[BUFFER];
                // write the files to the disk
                FileOutputStream fos = new FileOutputStream(providerDirectory.getAbsoluteFile() + File.separator + reqNam);
                dest = new BufferedOutputStream(fos, BUFFER);
                while ((count = zis.read(data, 0, BUFFER)) != -1) {
                    dest.write(data, 0, count);
                }
                dest.flush();
                dest.close();
            }
            zis.close();
            LogsModel.log(c,"System","finished extraction operation of required ZIP file: ["+zipFileName+"].");
            return reqNam;
        } catch (Exception e) {
            e.printStackTrace();
            LogsModel.log(c,"System","encountered the following Exception while trying to Extract the ZIP file: ["+zipFileName+"],Exception is: ["+e+"].");
            return null;
        }
    }

[Ahmed Kotb]

Henry Wong wrote:
WinRar supports many many different formats -- including the copyrighted rar format. If the cause is because you are using a format that isn't support, I don't know what to tell you.

File Format is ZIP , and after extraction i try to rename it as above in the code.

I used this method with Small files and it worked good , but when dealing with large files it throws that exception.

[Rob Spoor]

How large is "large"? If I remember correctly, Java's ZIP classes didn't support ZIP files of 4GB or larger until Java 7.

[Ahmed Kotb]

when downloading that file with FileZilla the extraction method working well, so i guess that the problem in the method which i am using for downloading(retrieveFile(String remoteFileName, FileOutputStream fos)) ...
I am using Apache Library (commons-net.jar), is there any problems for that library ?

[Ahmed Kotb]

Thanks to All

I found the Error

The Error was in Setting File Type Before Downloading it .

[Rob Spoor]

Ah yes, the dreaded ASCII / binary download problem. Downloading a binary file (like ZIP files) as if they were text will corrupt the file. That's what happened to you. When using binary or automatic for transferring you won't have this problem.