how to solve numberformatexception which getting edittext field in android

[Suzzane Pinto]

hi,
i have a edittext field which takes numeric oly.
i want to insert that value into database..
iam trying to do something like this

final EditText phone_number = ( EditText) findViewById(R.id.editText1);

 int myEditValue2=Integer.parseInt(phone_number.getText().toString());

and it gives numberformat exception....unable to parse

[Tim Moores]

Seems like the contents of the field is nor parseable into a number. Which value does it have? You should catch the exception regardless, as you don't want the app to crash just because someone accidentally typed a non-number.

[Suzzane Pinto]

hi;


i have written android:inputType="number" in xml.it alows to take numbers only....
and i want to insert it into the database to a numeric field only

[Tim Moores]

Tim Moores wrote:Which value does it have?

Tim Moores wrote:You should catch the exception regardless, as you don't want the app to crash just because someone accidentally typed a non-number.

An empty field would also be a non-number.

[Mohan Prasath]

Try to check for null and empty value in your "phone_number" object.

[Suzzane Pinto]

i caught the exception....the value it takes is numbers from 0-9.
how to get that ...??

[Suzzane Pinto]

final EditText phone_number = ( EditText) findViewById(R.id.editText1);

if(phone_number.getText().toString().length()==0)
{
phone_number.setError( "Mobile number is required!" );
}
myEditValue1 = phone_number.getText().toString();

myEditValue2=Integer.valueOf(myEditValue1);

IT SAYS UNABLE TO PARSE AS INTEGER

PLEASE SUGGEST

[Tim Moores]

Why is the code parsing the value after it has been found to be invalid?

[Suzzane Pinto]

actually ive put that in if else properly....

[Tim Moores]

Please don't mislead us by posting code that is not the code that you're using; that just makes it harder to help you.

[Suzzane Pinto]

i dnt knw why it is not parsing here....
iam entering number using getText().toString() ...now iits a string agn if i parse to integer...i think dats why it gives cannot parse and numberformatexception
is there any way to get the number entered as integer and pass directly...
please suggest

[Swastik Dey]

Are you entering any float or double values in edittext?

[Suzzane Pinto]

iam not entering any float or double value......just numeric....
and have android:inputType:number


ANY IDEA WHY SUCH PROBLEM

[Tim Moores]

If this was my problem I'd write the value that's passed to Integer.parseInt to the logcat output, so that I wouldn't have to guess what's going wrong.

[Suzzane Pinto]

i printed on log the value i pass to Integer.parseInt is getting....but after that it goes to catch numberformatException

[Suzzane Pinto]

I solved it using
Long value=parseLong(myeditText.getText().toString());

[shizuku Yakusa]

if((edt.getText()+"") == ""){
// Write your code

} else {
// Write your code

}

[Tim Moores]

shizuku Yakusa wrote:if((edt.getText()+"") == "")

Very, very wrong. Read up on the difference between string equality and object equality. What the "==" does here is exactly the wrong one - don't compare strings using "==".