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Logic below not followed

 
Greenhorn
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What is the output of the following code?



Correct Answer

Monkey

I did not understand this logic. Please explain
 
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Hi,

I just added two print statements:


here is the output:

boo2==>false
boo3==>true
Monkey

The below concepts would help to understand the output:

Default Values:

In this class, the variable 'boo2' is not initialized. If the member and static variables are not initialized, they would get default values. example, booleans get a default value of false, integers get a default value of 0.

Hence the value of 'boo2' is false in this example

instanceof operator:
This operator is used to check whether an object falls under certain type. Every object inherits the class 'Object'. So the variable boo3 is set to true

Order of precedence:

& operator has higher precedence than the | operator.

So, (boo1 & boo2 | boo2 & boo3 | boo2 ), after substituting the values will be like below:

( true & false | false & true | false ) will result in
( false | false | false ) will result in
( false )

Similarly, ( boo3 & boo2 | boo2 & boo1 | boo2 | boo1) will result in

( true & false | false & true | false | true )
( false | false | false | true )
(true)


Hope this helps,

Regards


 
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