XPath - match nodes on two levels

[Jeppe Sommer]

Hi.

I want to use xpath to match the second companySetup node in the XML below (if and only if two criterias matches). Let's say I want the companySetup with the attribute companyID="1" and the sub node /companySetup/canteen/canteenID with the text value = 50.

I tried to execute the xpath below, but it returns the first companySetup node which has the canteenID text value = 20.

Any help would be appreciated.

String expression = "/invoice/companySetup[@companyID='1'] | /invoice/companySetup/canteen/canteenID[text()= '50']";
org.jdom.Element e_companySetup = ( ( org.jdom.Element  )( org.jdom.xpath.XPath.selectSingleNode ( doc , expression ) ) );

The XML looks like:

<invoice>
<companySetup companyID="1">
	<canteen>
	    <canteenID>20</canteenID>
	</canteen>
</companySetup>
<companySetup companyID="1">
	<canteen>
	    <canteenID>50</canteenID>
	</canteen>
</companySetup>
<invoice>

[g tsuji]

Like this.

//String expression = "/invoice/companySetup[@companyID='1'] | /invoice/companySetup/canteen/canteenID[text()= '50']";
String expression = "/invoice/companySetup[@companyID='1' and canteen/canteenID='50']";

[Jeppe Sommer]

Thanks.

Simple and easy

[Jeppe Sommer]

How can I get the list of all canteenIDs (50,51,52) which belongs to companyID="1"?

I have tried with the expressions:
String expression = "/invoice/companySetup[@companyID='1']/canteen/canteenID"

and

String expression = "/invoice/companySetup[@companyID='1' and canteen/canteenID]"

but it didn't work.

<invoice>
<companySetup companyID="1">
	<canteen>
	    <canteenID>20</canteenID>
	</canteen>
</companySetup>
<companySetup companyID="1">
	<canteen>
	    <canteenID>50</canteenID>
                    <canteenID>51</canteenID>
                    <canteenID>52</canteenID>
               	</canteen>
</companySetup>
<invoice>

[g tsuji]

How can I get the list of all canteenIDs (50,51,52) which belongs to companyID="1"?

I have tried with the expressions:
String expression = "/invoice/companySetup[@companyID='1']/canteen/canteenID"

This path seems just fine. Only, if you continue to use selectSingleNode() as shown in your first post, you won't possibly get them as such. You can certainly use selectNodes() (read the documentation) as a sort of natural continuity.

But you should notice from the documentation that selectSingleNode() and selectNodes() and many others are deprecated for some time. You should look for the use of XPathExpression and Filter etc... to do it in the future. It's up to you.