how to produce dynamic path of searched file?

[derick nial]

This is in my jsp

 img src="img/no_avatar.png" id="Image1"width="220" height="230" /> <p>
<div align="left"> <input name="uploadAvatar" id="uploadAvatar" type="file" size="20" /></div> 

This is in my servlet:

String uploadAvatar = request.getParameter("uploadAvatar");
LogHandler.getLogger().debug("uploadAvatar-->" + uploadAvatar);

byte[] newAvatar= null;
int maxLength = 1000 * 1024;

            if (uploadAvatar == null || uploadAvatar.equals("")) {
                newAvatar = null;
            } else {
                if (uploadAvatar.endsWith(".jpg") || uploadAvatar.endsWith(".png") || uploadAvatar.endsWith(".gif")) {

                    Path source = Paths.get("C:\\Users\\Acer\\Desktop\\mine\\images\\Extra\\" + uploadAvatar);
                    String mimeType = Files.probeContentType(source);
                    System.out.println("mimeType--->" + mimeType);

                    newAvatar = Files.readAllBytes(source);
                   }
           }

My question is, how to make this

"C:\\Users\\Acer\\Desktop\\mine\\images\\Extra\\"

dynamic?
i mean i don't want to write hardcoded of the address path.

i have tried

UserController ur = new UserController();
Class cls = ur.getClass();

  // finds resource relative to the class location
URL url = cls.getResource(uploadAvatar);
 System.out.println("Value = " + url); //the value returns null

 // finds resource relative to the class location
  url = cls.getResource("newfolder/uploadAvatar");
System.out.println("Value = " + url);//the value returns null

i also have tried

Files f = new Files(uploadAvatar);
f.getAbsolutePath();
f.getPath();
f.getCanonicalFile();

but the address returned was:

C:\Program Files (x86)\Apache Software Foundation\Tomcat 7.0\bin\sunset.jpg

what i really want is:

C:\Users\Acer\Desktop\mine\images\Extra\sunset.jpg

I would greatly appreciate it if you kindly give me some feedback. thanks.

[Joe Ess]

Why would you post a new topic when we already have a conversation here?. Do you want to waste the community's time having someone else answer questions we've already covered?

I already answered why this doesn't work in your previous topic:

Files f = new Files(uploadAvatar);  
f.getAbsolutePath();  
f.getPath();  
f.getCanonicalFile(); 

As for this code:

URL url = cls.getResource(uploadAvatar);  
 System.out.println("Value = " + url); //the value returns null  

You don't tell us where your image is located. In your previous topic, I told you that you needed to package the image with your web application. Did you do that? The javadoc for Class explains the rules the class loader uses to find a resource.

[derick nial]

You don't tell us where your image is located.

the image is in here----> C:\Users\Acer\Desktop\mine\images\Extra\sunset.jpg

In your previous topic, I told you that you needed to package the image with your web application.

how to do this?

[Joe Ess]

derick nial wrote:

You don't tell us where your image is located.

the image is in here----> C:\Users\Acer\Desktop\mine\images\Extra\sunset.jpg

Why does it have to be this directory? When you deploy your application to another computer, someone have to create an "Acer" user on that machine in order to put an image in that directory.

derick nial wrote:

In your previous topic, I told you that you needed to package the image with your web application.

how to do this?

How are you deploying your application?