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Contact List Program

 
Greenhorn
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I am new to programming and object oriented design. This is my last requirement to finish my bachelors degree (not in programming). I am a bit confused with how to make object oriented work, and nothing I look at seems to help. The assignment is to create a contact list that uses inheritance, polymorphism,and collections. I need a contact list that stores two types of contacts: business and personal. I need prompt 1 to add a contact and then ask 1 for personal or 2 for business. Prompt 2 will allow user to display the output of a chosen contact and prompt 3 will quit.

I have the following class and subclasses built. I am pretty sure the classes are built right but after adding either type of contact, when I choose 2 in order to view I can't see anything it just returns me [contactlist.PersonalContact@55f96302]. Any help would be awesome, I just need to get through this, then I will gladly leave programming to those that know what they are doing.

I apologize for the long post but thought I should show everything.

Here is my main:



Contact Class:



Business Contact Subclass:



Personal Contact Subclass:

 
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Tim Davis wrote:... it just returns me [contactlist.PersonalContact@55f96302].


That's the kind of output you get when you don't override the toString() method.

Your class PersonalContact does not have a toString() method. Java doesn't know automatically how you want a contact to be converted to a string. You should override the toString() method in class PersonalContact.
 
Tim Davis
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So I put my overrides in as follows:

Personal Subclass:



Business Subclass:



I am still throwing the same message. This is all I need to override correct?
 
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When you write something like this:



...Java automatically looks for a method called toString(). If you don't override it, it will fall back to Object's toString() method, which is what you're seeing. Add this:



..to your two Contact subclasses.
 
Tim Davis
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I know this is very basic for you guys here but it I just don't seem to be grasping it. I have change my subclass code as follows:

When I do this it tells me a return statement is needed. Isn't that what I am doing by saying System.out.println(this.dateOfBirth)? If I include the line return null:

Now I get the following on my output:
[1] Add contact
[2] View all contacts
[3] Quit
Choose : 1
Please enter Specify the contact type (1) Personal or (2) Business:
1
First Name: John
Last Name: Doe
Address: 123 Anywhere St. Anywhere, AL 12345
E-mail address: jdoe@live.com
Phone number: 123-456-7890
Date of Birth (MM/DD/YYYY): 01/01/1980

[1] Add contact
[2] View all contacts
[3] Quit
Choose : 2
John
Doe
123 Anywhere St. Anywhere, AL 12345
jdoe@live.com
123-456-7890
01/01/1980
[null]

[1] Add contact
[2] View all contacts
[3] Quit
Choose : 3
BUILD SUCCESSFUL (total time: 1 minute 12 seconds)

It allows me to put in the information but then when I choose 2 to view it returns the info but includes [null] at the end.
 
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toString() needs to return a String formatted the way you'd like to see it. Do not put print()'s inside of the toString() method.
 
Tim Davis
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So when I add a business contact and go to view it I want to see everything from the main Contact class as well as jobTitle and organization from the business contact subclass. Then when I write my code as follows:


I can return a single value such as jobTitle and will get it to display properly but when I try return String(BusinessContact) it tells me can not find symbol.
 
Carey Brown
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Tim Davis wrote:So when I add a business contact and go to view it I want to see everything from the main Contact class as well as jobTitle and organization from the business contact subclass. Then when I write my code as follows:


I can return a single value such as jobTitle and will get it to display properly but when I try return String(BusinessContact) it tells me can not find symbol.


Don't call view Contacts as this calls println() which I said you don't want to do in toString().
More like

And you should use getFirstName() and not getfirstName(), the 'F' should be capitalized.
 
Tim Davis
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That option definitely works but I was looking to have it output in a list not a line across.

Right now I am getting first name = John, last name = doe, etc....

I was looking for

first name = John
last name = Doe
etc....

That is why I was using System.out.println(this.firstName), etc... ao I could list it out.

How can I do this using return?
 
Carey Brown
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Tim Davis wrote:That option definitely works but I was looking to have it output in a list not a line across.

Right now I am getting first name = John, last name = doe, etc....

I was looking for

first name = John
last name = Doe
etc....

That is why I was using System.out.println(this.firstName), etc... ao I could list it out.

How can I do this using return?


Simply add some new-line characters into the mix where you want line breaks.
 
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In which case you should not simply add the line separator characters. Try this sort of thing:-
return String.format("First name: %s%nLast name: %s", firstName, lastName);
You can read about the % tags here (comprehensive but not easy) here and here (only simple examples but easier to read).
 
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