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# Java printing square pattern numbers --missing part

Ranch Hand
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Hello, I would to print the following pattern, but somehow, I don't get the first column and the first row, which I don't really understand. Thanks for explanation !

00 10 20 30 40 50 60 70 80 90
01 11 21 31 41 51 61 71 81 91
02 12 22 32 42 52 62 72 82 92
03 13 23 33 43 53 63 73 83 93
04 14 24 34 44 54 64 74 84 94
05 15 25 35 45 55 65 75 85 95
06 16 26 36 46 56 66 76 86 96
07 17 27 37 47 57 67 77 87 97
08 18 28 38 48 58 68 78 88 98
09 19 29 39 49 59 69 79 89 99

here is the little code :

Sheriff
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This is a classic "off by one" problem. Think about when your for loop ends. From x=0 to x<9. How many is that?

Bartender
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Did you try going through the code by hand and see what is happening? You start off by setting x to zero, then increment x, so x is now one. Then you enter the inner loop and add ten to x, so x is eleven when you first print it. Also, if you want 10 columns, why do you use x<9 for the inner loop termination condition?

Marshal
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Don't use \n. Use
System.out.println();
Don't use simple print(x). Use
System.out.printf(%02d ", i);

Or better still, append the numbers and space and System.lineSeparator() to a StringBuilder; then you only need one print call.
System.out.println(myStringBuilder);

Frank Poupard
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