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How do I find Consecutive Letters?

 
Greenhorn
Posts: 23
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Sorted String İnput: 1, 2, 2A, 2B, 2C, 3, 3A, 4, 5, 6, 32C, 32D, 50, 51/1, 51/2, 60, 61, 62, 200-2E, 200-2F, 200-2G, 200-2H, 201C, 201/21P, 201/21R, 201/21S,300,300A,301-2A, 542/2K, 542/2L,583-1, 583-585D, 583-585E, 605, 605A, 605B,605C 800A.
Question is about merging consecutive values into a range. E.g.4,5,6 =[4-6] , 2A, 2B, 2C are consecutive values, so range is 2[A-C]. No other values can be in a range.
• General pattern: number[chars][A-Z]
If chars is present, then they have to be equals() to be in a sequence. If the trailing letter is present, they have to be consecutive to have a sequence
A sequence is then abbreviated using: first + "-" + last
51/1, 52/1, 53/1 ==> not merged
51/1A, 51/1B, 51/1C ==> 51/1[A-C]
51/1A, 52/1B, 53/1C ==> [51-53]/1[A-C]
It should be listed as follows.

output:
1  
2
2[A-C]
3
3A
[4-6]
32[C-D]
50
51/1
51/2
[60-62]
200-2[E-H]
201C
201/21[P-S]
300
300A
301-2A
542/2[K-L]
583-1
583-585[D-E]
605
605[A-C]
800A






output= merged: [1, 2, 2A, 2B, 2C, 3, 3A, [4-6], 32C, 32D, 50, 51/1, 51/2, [60-62], 200-2E, 200-2F, 200-2G, 200-2H, 201C, 201/21P, 201/21R, 201/21S, 300,300A,301-2A,542/2K, 542/2L,583-1, 583-585D, 583-585E, 605, 605A, 605B,605C 800A]

I'm waiting for your help.thanks.
 
Sheriff
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You've already asked this question here and it looks like you were getting close to what you need in that other thread. Please continue the discussion in the original thread.
 
Don't get me started about those stupid light bulbs.
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