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Writing fully optional and functional method that maps String to natural number

 
Ranch Hand
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I'm trying to write fully functional and optional method that maps optional String -> optional natural number (let suppose natural numbers begin with 0)
This is what I wrote so far:



However my intuition tells me that it is possible to write this function with using only interfaces from Functional library instead using if statements.
 
Marshal
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I'm sure you're right. My rough idea goes like this:

Apply .stream() to the Optional<String> and you'll get a Stream<String> with 0 or 1 entries. You can use filter() instead of your if-statement, that's what filter() is for, then you need some kind of map() to convert a String to an int if you have one, then you need to make the result into an Optional. Give it a try.
 
Rancher
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Andrzej, your intuition is correct.  Optional has map() and filter() methods - both of these are designed to do nothing on an empty Optional.  So you don't have to check isPresent() before calling these methods - they will do that for you, internally.

Converting to stream() is unnecessary since Optional already has the needed methods.  
 
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