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parseInt()

 
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Hi, could you help me understand this code, please?



The output is "trouble 12.3". So, f becomes 12.3, then it is changed into a String s "12.3" and then "12.3" is passed into parseInt method. Why does it throw NumberFormatException if when I write Integer x = Integer.parseInt("12.3"); System.out.println(x); the output will be 12 (no exception)?

Thank you,

Tonya
 
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Welcome to the Ranch

Have you looked up the documentation for Integer#parseInt()? That tells you the format of String permissible as an argument. I don't know how you got the following code to run normally:-

jshell> Integer x = Integer.parseInt("12.3"); System.out.println(x);
|  Exception java.lang.NumberFormatException: For input string: "12.3"
|        at NumberFormatException.forInputString (NumberFormatException.java:68)
|        at Integer.parseInt (Integer.java:652)
|        at Integer.parseInt (Integer.java:770)
|        at (#1:1)

 
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