Originally posted by robbie keane:
how can i pass an argument in a .jacl script from command line? I'm trying to run the foll command from command prompt:
wsadmin -conntype SOAP -host 172.19.39.53 -port 8880 -f "uninstWASJacl.jacl"
and i want to pass some argument in this "uninstWASJacl.jacl" file (which i can use within the file as "$arg").
Thanks in advance.
Simply do this:
wsadmin -conntype SOAP -host 172.19.39.53 -port 8880 -f "uninstWASJacl.jacl" argument1 argument2
And it'll be picked up by the jacl script. As you've said, in the jacl script use $argv.