Smita Chopra

I recently attended an interview with HCL Noida.

They have the rudest HR I have ever met. They would not leave any chance to insult the candidate they were interviewing.
THe guy who interviewed me was extremely short tempered and became angry even when I made some queries.
To quote one instance he asked me how much salary I expected. I asked, if he had a range in mind for me.
He apparently bacame very upset with this and told me "I am asking you a simple question about salary and you are counter questioning me".

Anyways when he asked me at the end of the interview if I had any questions I told him he was very rude and I would not like to work for a company where people like him existed.
I know this is very unprofessional to do so but that is all I could think of at that time.

Is there any other way than using 2 Dimensional Arrays, I find them extremly confusing to use.
Thanks

package com; public class NumericToWords { public static void main(String[] args) { new NumericToWords().performConversion(10); new NumericToWords().performConversion(7); new NumericToWords().performConversion(15); new NumericToWords().performConversion(34); new NumericToWords().performConversion(79); } public void performConversion(int number) { // convert the number }

The problem with this code is that it does a lot of if conditions. If I need to increase it to display hunderds I'll need to add another if condition checking if the number is greater than 99 and less than 1000 ....
Can someone please suggest a better approach in simple words?

(Marilyn removed some code)
[ August 03, 2005: Message edited by: Marilyn de Queiroz ]

Thanks for your replies. This is what I have done so far.

package com; import java.util.*; public class Booking { private static String[][] seats = { new String[5], new String[5], new String[5], new String[5], new String[5], new String[5], new String[5], new String[5], new String[5], new String[5], new String[5], new String[5], new String[5], new String[2], }; public static void main(String[] args) { /* Initialize each seat to empty in the beginning */ for(int i=0; i<seats.length; i++) { for(int j=0; j<seats[i].length; j++) { seats[i][j] = "empty"; } } new Booking().book(6); new Booking().book(5); new Booking().book(3); new Booking().book(1); new Booking().book(2); new Booking().book(4); new Booking().book(3); for(int i=0; i<seats.length; i++) { for(int j=0; j<seats[i].length; j++) { System.out.println(seats[i][j]); } } } public void book(int number) { if (number > 5) { System.out.println("Sorry Cannot book more than 5 seats"); return; } /* Code for booking seat */ } }
Am I going in the right direction?
How to find if consecutive seats are empty? Check each seat?
Thanks
Thanks
[ August 02, 2005: Message edited by: Smita Chopra ]

Originally posted by SAYED RAFI:
Hi

Thanks to Victor & Smitha : Information sent by you is very usefull to me :
As iam joining Accenture on 8th Aug.2005.

Cheers : Sayed

Congratulations!
Which location are you joining?

Originally posted by Thomas Whalen:

If personA asks for tickets, then
...Ask personA for number of tickets being requested
...Get number of tickets
...If number of tickets is greater than five then
......Reject ticket request
...Else
......Loop through each row
.........If number of available seats is >= than request then
............Fill seats in that row equal to request
...............Set number of seats available minus request
.........End If
......End Loop
...End If
End If

Am I understanding the problem correctly?

Thanks for you input.

But what if second..third...tenth person comes and asks for a ticket. You'll have to see which all seats have been filled. Of the vacant seats you'll have to look for consecutive seats. If consecutive seats are not available you'll have to assign them dispersed seats and update your list of filled seats.
Thanks

Thanks for replying

Originally posted by Thomas Whalen:
I'm only a mere beginner, but...why are you getting questions in a job interview (I thought only highly qualified Java programmers got interviews anymore) and asking them in a beginner forum? :-)

That is becaue I am a beginner myself. Graduated 15 days ago.

Recently in an interview I was asked to write code in Java for the following problem.

In a train compartment there are 67 seats...13 rows of 5 (3 by2) seats
and the last row has 2 sets. A person cannot book more than 5 seats. If a
person is booking then it should be such that maximum people of the group get
consecutive seats.

I can't develop logic for this and which datastructure should I use to store seats which have been assigned and still empty.
Please give me pointers in this regard.
Thanks

Originally posted by Steve Morrow:
First link from Google:

http://www.rgagnon.com/javadetails/java-0426.html

THanks a lot.

How can I convert numeric to words. Say if the user supplies 465 convert it to four hundred and fifty six, convert 34 to thirty four and so on.
Please give me some pointers in this regard.

Thanks.

Originally posted by Joel McNary:
Perhaps the String.replaceAll() method is what you want. It takes a regular expression and replaces all occurrances of the regular expression with the substitute value.

String newString = oldString.replaceAll("[@%\\.\\*]", "");

This replaces all occuranecs of @, %, ., and * with the empty string, thereby eliminating them from your string.

Your way could work, albeit much less efficiently, with simply elimating the characters instead of replacing them with a dollar sign, akin to:

public String parse(String value) { char[] charValue = value.toCharArray(); for(int i=0; i<charValue.length; i++) { char aChar = charValue[i]; if(aChar != '@' && aChar != '%' ...etc){ valReturn = valReturn + charValue[i]; } } return valReturn; }

Thanks a lot. It was much easier than I thought

I have a method which accepts a String and after eliminating some unnecessary characters like @,* etc it returns the String.

I have not been able to totally eliminate the not allowed characters, but have managed to replace them with a $ sign.
Can someone please tell me how to eliminate the uneeded characters.

public String parse(String value) { char []notAllowed = {'@', '%', '.', '*'}; char[] charValue = value.toCharArray(); String valReturn = ""; for(int i=0; i<charValue.length; i++) { for(int j=0; j<notAllowed.length; j++) { if(charValue[i] == notAllowed[j]) { charValue[i] = '$'; } } } for(int i=0; i<charValue.length; i++) { valReturn = valReturn + charValue[i]; } return valReturn; }
[ July 29, 2005: Message edited by: Smita Chopra ]

Thanks a lot for the information.

What are the data structures in Java?
Thanks

Thanks a lot, that was great.