Mike Jenkins

I use Apache Commons codec Base64 encoding and decoding methods to fetch Intranet Domain login name only.
Is this considered an acceptable safe practice and/or is there any securty or any other issue with Base64 encoding and decoding?

The Head First book is good but if you really want to learn with a great mock database example, use the http://simple.souther.us/SimpleTable.war. I read many many books and articles and none come close to the http://simple.souther.us/SimpleTable.war example. I recommend the SimpleTable example to alot of people.
[ May 08, 2008: Message edited by: Mike Jenkins ]

Thanks again for all info.

I want to use this for File I/O work.

Originally posted by Bear Bibeault:
Are you really looking for the location of the Tomcat installation, or the location of the web app (which may or may not be co-located)? If the former, I hear many whistles and see many red flags. What would you do with this information?

Thanks,

I need the location of the Tomcat installation only.

Is there a method or something I can use in my Java helper class to find the Tomcat Home location on the server?
For example here is what the path might look like on the Server: C:\TomcatHome\webapps\myfile.jsp

In other language like Cold Fusion I can put in something like ExpandPath function and it will grab the Server Cold Fusion JRUN location: #ExpandPath#webapps\myfile.jsp

Does Java have anything like that?
[ May 05, 2008: Message edited by: Mike Jenkins ]

Originally posted by Bear Bibeault:
Actually it's a change in the Servlet Specification, not Tomcat.

The change from Servlets 2.3 to 2.4 mandated the change from a DTD to XML Schema.

Thanks,
The difference is the beginning part of my web.xml?
DTD? <?xml version="1.0"?> <!DOCTYPE note [ <!ELEMENT note (to,from,heading,body)> <!ELEMENT to (#PCDATA)> <!ELEMENT from (#PCDATA)> <!ELEMENT heading (#PCDATA)> <!ELEMENT body (#PCDATA)> ]> .....

xml?
<?xml version="1.0" encoding="ISO-8859-1" ?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"> ....

In Tomcat 6 they changed web.xml to a schema.
What is the difference between a schema version of web.xml in Tomcat 6
and a non schmea version of web.xml like the one they used in 4.1.27?
[ April 15, 2008: Message edited by: Mike Jenkins ]

Jeanne,

Thanks and you always give great help and advise on Javaranch!

I was wondering if there is anyway to click on a button or link on JSP and it print the JSP web page onto a CD where I can actually have the web page show on a CD? I guess Java would have to create a powerpoint of the page and be able to access the CD on the Windows OS. Is this possible?
[ November 29, 2007: Message edited by: Mike Jenkins ]

Sorry I dont understand what you mean by putting it in the request?

I dont have EL or JSTL in my Tomcat 4.1.27 due to restrictions but hoping to get it sometime next year.

Anyway to condense the declarations below?
int counter = 0; int streets = 0; int schools = 0; int people = 0;



I was hoping for something like this but it doesnt work:
int counter, streets, schools, people = 0;

I have a Servlet that checks for information and if there is an issue it forwards the message to presentation page (JSP). Now I want to stop using conditions in scriptlets in the JSP. Please advise how I can do it in this situation in my Tomcat 4.1.27 container:

Servlet that forwards to JSP:
... String gotopage = ""; if(mydata == 1) { gotopage = /"pager.jsp?mymessage=err"; } else if(mydata == 34 { gotopage = /"pager.jsp?mymessage=duper"; } else { gotopage = /"pager.jsp?mymessage=proc"; } RequestDispatcher dispatcher = getServletContext().getRequestDispatcher(gotopage); dispatcher.forward(request, response); ...

JSP
<% String mymessage = request.getParameter("mymessage") if(mymessage.equals("err")) { out.println("Error on the page"); } else if(mymessage.equals("dup")) { out.println("Duplicate issue."); } else if(mymessage.equals("proc")) { out.println("Process message issue"); } %>
I was thinking maybe a bean or regular Java class to handle this but not sure how. Here would be my method in a Java class:
public void getMessage(String msg) { if(msg.equals("err")) { out.println("Error on the page"); } ... }

Then I would put the method in a bean or what in JSP?
The Servlet would stay the same?

I have JNDI working with my Oracle 9i database using my server.xml file in my local Tomcat 4.1.27. Now I need to put my webapp on the server and I wont get access or be able to touch server.xml on the server.

Please advise how I can get the JNDI to work without using server.xml. I tried putting the <context> info I had in server.xml into mywebappname root and call it mywebappname.xml and that didnt work. I also tried that with creating a context.xml and that didnt work. Both gave me back error message: Cannot create JDBC driver of class '' for connect URL 'null'

Is this something that can be done in Tomcat 4.1.27??

Here is what I have working in my server.xml that connects to Oracle databse with no problems:
server.xml(C:\jakarta-tomcat-4.1.27\conf)

<Context path="/DBTest" docBase="DBTest" debug="5" reloadable="true" crossContext="true"> <Logger className="org.apache.catalina.logger.FileLogger" prefix="localhost_DBTest_log." suffix=".txt" timestamp="true"/> <Resource name="jdbc/TestDB" auth="Container" type="javax.sql.DataSource"/> <Resource name="jdbc/myoracle" auth="Container" type="javax.sql.DataSource"/> <ResourceParams name="jdbc/myoracle"> <parameter> <name>factory</name> <value>org.apache.commons.dbcp.BasicDataSourceFactory</value> </parameter> <parameter> <name>driverClassName</name> <value>oracle.jdbc.OracleDriver</value> </parameter> <parameter> <name>url</name> <value>jdbc :-o racle:thin:@127.0.0.1:1521:mysid</value> </parameter> <parameter> <name>username</name> <value>scott</value> </parameter> <parameter> <name>password</name> <value>tiger</value> </parameter> <parameter> <name>maxActive</name> <value>20</value> </parameter> <parameter> <name>maxIdle</name> <value>10</value> </parameter> <parameter> <name>maxWait</name> <value>-1</value> </parameter> </ResourceParams> </Context>





web.xml
<resource-ref> <description>Oracle Datasource example</description> <res-ref-name>jdbc/myoracle</res-ref-name> <res-type>javax.sql.DataSource</res-type> <res-auth>Container</res-auth> </resource-ref>



database connection part

Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup("java:/comp/env"); DataSource ds = (DataSource)envContext.lookup("jdbc/myoracle"); Connection conn = ds.getConnection(); //etc.
[ November 08, 2007: Message edited by: Mike Jenkins ]

2) if you want to be a bit more flexible, create a hidden param in the form with a comma-delimted list of the names in the desired order. The servlet can obtain and split this value to determine the names to retrieve in order.

I'd opt for the de-coupling that the second solution provides even though it's a tad more work.

I like this info.
Thanks for your time and guidance!
[ October 25, 2007: Message edited by: Mike Jenkins ]

Start by explaining what the order is. Is it the order of the fields on the form? If so, is the list of field names dynamic, or are they known in advance?

Thanks for your time on this!

I want it listed in the order of fields as shown on the form as seen below and the list of field names are known in advance.

Here is my JSP Form page with 6 out of the 15 field inputs listed:
<form action...> First Name <input type="text" name="firstName"><br> Last Name<input type="text" name="lastName"><br> City <input type="text" name="city"><br> County <input type="text" name="County"><br> Project Info <input type="text" name="projInfo"><br> Main Status <input type="text" name="mainStatus"><br> //on and on for 9 more already known in advance field names.... ....... <input type="submit" value="Submit">
[ October 25, 2007: Message edited by: Mike Jenkins ]