beu curt

I've been reading this for awhile now, but I just can't figure the flow and idea of this code.

if(view_choice.equals("a")){ // BLOCK TO EXECUTE WHEN USER SELECT A int i, j; String t=""; String t1=""; for(i = 0; i < person_count; i++) //LOOP TO SORT NAMES IN ALPHABETICAL ORDER { for(j = 1; j < (person_count-i); j++) { int compare = person[j-1][0].compareTo(person[j][0]); if(compare >0){ t = person[j-1][0]; t1= person[j-1][1]; person[j-1][0]=person[j][0]; person[j-1][1]=person[j][1]; person[j][0]=t; person[j][1]=t1; } } } System.out.println("\t Name -- \t -- Telephone --"); // DISPLAY SORTED NAMES for(int count=0;count<person_count;count++) { System.out.print("\t"+person[count][0]+" \t----"); System.out.println("\t"+person[count][1]); } }

Any explanation would be very helpful, thank you

fred rosenberger wrote:

try this:
System.out.printf("\t%f", table[r][c]);

It stopped the error but it did not align the elements. Thank you

Here is what I am trying

double[][] table = new double[][] {{x1,x4,x7},{x2,x5,x8},{x3,x6,x9}}; for (int r=0; r<table.length; r++) { for (int c=0; c<table[r].length; c++) { System.out.printf("\t%f" + table[r][c]); } System.out.println(""); }

Here is my error


[color=red]Exception in thread "main" java.util.MissingFormatArgumentException: Format specifier 'f'[/color]



What I am trying do is align all the elements regardless of the place value.

I'm still not able to align the elements.

Here is what I am doing
double[][] table = new double[][] {{x1,x4,x7},{x2,x5,x8},{x3,x6,x9}}; for (int r=0; r<table.length; r++) { for (int c=0; c<table[r].length; c++) { System.out.printf("\t" + table[r][c]); } System.out.println(""); }

If the answer to equation exceeds place value compare to the element on its side, it messes up the pattern.
When I tried to use %f it gave me an error.
------------------------------------ 1.0 244.0 24.0 22432.0 42.0 24224.0 244.0 24.0 4242.0

I managed it

Did you use printf?

Hello

I have this output that looks like this: a cd` fg ij a cd fg ij a cd fg ij ab cd fg ij ab cd fg i j ab cd fg ij ab cd fg ij ab cde fgh ij ab cde fgh ij I want it to look like this: a cd` fg ij a cd fg ij a cd fg ij ab cd fg ij ab cd fg ij ab cd fg ij ab cd fg ij ab cde fgh ij ab cde fgh ij

The values are in double. How can attain that format?
Thak you very much.
LOL I can't make the column straight But what I am trying to do is align all the elements.

Wouter Oet wrote:No. More like this:

variable x = input()
loop
variable result = calculation(x)
print result
x = result
end loop

You made it work I owe you my life.

Thank very much.

Wouter Oet wrote:Then just assign the result to the input variable at the end of an iteration.

example:
equation = x + 2
input=1

1+2=3
x = 3

x+2
3+2=5
x = 5

x+2
5+2=7

and so on

you meant like this?
m = (1-2*x)/x; x2= (1-2*m)/m; x3= (1-2*x2)/x2; x4=(1-2*x3)/x3; x5=(1-2*x4)/x4; x6=(1-2*x5)/x5; x7=(1-2*x6)/x6; x8=(1-2*x7)/x7; x9=(1-2*x8)/x8; x0=(1-2*x9)/x9;

Wouter Oet wrote:I'm not sure what your problem is. Is it that it only asks for input once? In that case that is because you're only asking for input once, it is not in the for loop. If it's regarding the calculation then you need to provide us with more information.

By the way: look at the difference between System.out.print and System.out.printf.

Yep it only asks for one input. The answer for the first input should be the the next value to substituted.
example: equation = x + 2 input=1 1+2=3 x+2 3+2=5 x+2 5+2=7 and so on

Hi!

So basically this program will stop at 15 iterations. My problem is I am not able to substitute the value of the answer to the equation.

Here is the code
package javaapplication2; import java.lang.*; import java.util.Scanner; public class Fixed { public static void main(String args[]) { Scanner word=new Scanner(System.in); System.out.println("xl"); double x = word.nextDouble(); double x2 = 0.0; double m = 0.0; double dx = x2-x; double dy = 0.0; int No = 0; for (int i = 0; i < 15; i++) { m= x2; m = (1-2*x)/x; dx = x-x2; dy = Math.abs(((x-x2)/x)*100); if(No>x){ System.out.println("Please enter another Input"); } else { System.out.printf("Please insert another Input"); } System.out.printf("Number of Interation is: " + i); System.out.printf(" Root obtained: " + m); System.out.printf(" Estimated error: " + dx); System.out.println(" A.R.A. error: " + dy); } System.out.println("*****************"); System.out.println(" Root obtained: " + m); System.out.println("Estimated error: " + dx); System.out.println(" A.R.A. error: " + dy); } }


The output should be

x1 = -1.5 x2 = -2.66666666667 x3 = -2.375 x4 = -2.42105263158 x5 = -2.41304347826 x6 = -2.41441441441 x7 = -2.41417910448 x8 = -2.4142194745 x9 = -2.41421254801 x10 = -2.41421373641

But the one I am getting is
x1 = -1.5 x2 = -1.5 x3 = -1.5 x4 = -1.5 x5 = -1.5 x6 = -1.5 x7 = -1.5 x8 = -1.5 x9 = -1.5 x10 = -1.5


I am really getting frustrated, I can't figure it out. Any help would be very helpful.

Thank you

Henry Wong wrote:
Interesting homework problem ...

Basically, this is an sort problem, except the sorting is done for you. Normally, the initial unordered list is provided, and you have to sort it -- using an algorithm that moves the elements.

Here, the problem is... you don't know the original unordered list, but you do know the moves that it takes to sort them. So, given an unordered (and unmarked) list, and the moves it takes to sort them, find out the ordering of the original list.

Henry

Thanks, but I still don't get it

I have read it more than 100+, but I still can't figure it out.
The problem is confusing and I don't get what it wants me to do.

In Byteland it is always the military officer's main worry to order his soldiers on parade correctly.
Luckily, ordering soldiers is not really such a problem. If a platoon consists of n men, all of them have different rank (from 1 - lowest to n - highest)
and on parade they should be lined up from left to right in increasing order of rank.

Sounds simple, doesn't it? Well, Sgt Johnny thought the same, until one day he was faced with a new command.
He soon discovered that his elite commandos preferred to do the fighting, and leave the thinking to their superiors.
So, when at the first rollcall the soldiers lined up in fairly random order it was not because of their lack of discipline, but simply
because they couldn't work out how to form a line in correct order of ranks. Sgt Johnny was not at all amused, particularly as
he soon found that none of the soldiers even remembered his own rank. Over the years of service every soldier had only
learned which of the other soldiers were his superiors. But Sgt Johnny was not a man to give up easily when faced with a
true military challenge. After a moment's thought a solution of brilliant simplicity struck him and he issued the following
order: "men, starting from the left, one by one, do: (step forward; go left until there is no superior to the left of you; get back in line).".
This did indeed get the men sorted in a few minutes. The problem was solved... for the time being.

The next day, the soldiers came in exactly the same order as the day before, and had to be rearranged using the same method.
History repeated. After some weeks, Sgt Johnny managed to force each of his soldiers to remember how many men he passed
when going left, and thus make the sorting process even faster.

If you know how many positions each man has to walk to the left, can you try to find out what order of ranks the soldiers initially line up in?
Input

The first line of input contains an integer t<=50, the number of test cases. It is followed by t test cases, each consisting of 2 lines.
The first line contains a single integer n (1<=n<=200000). The second line contains n space separated integers wi, denoting how far
the i-th soldier in line must walk to the left when applying Sgt Johnny's algorithm.
Output

For each test case, output a single line consisting of n space separated integers - the ranks of the soldiers, given from left to right
in their initial arrangement.
Example

Input:
2
3
0 1 0
5
0 1 2 0 1

Output:
2 1 3
3 2 1 5 4

Any explanations would be very helpful.
Thank you

Campbell Ritchie wrote:Please find the class whose name you are getting the problems with, and tell us exactly where you have got the .class file.

This is the whole program. I posted everything.

I think the problem is line number 8:
private AddressBookEntry[] list;

Christophe Verré wrote:The compiler does not find the AddressBookEntry class because it's not in the CLASSPATH
1. Where is AddressBookEntry.class ?
2. How did you compile AddressBook ?

A big noob here, can't understand what you are trying to explain.
sorry

The program is an Address Book. and I cant get rid of the "cannot find symbol class" error, what should I do?

here is the code:
package Project1; import java.io.*; public class AddressBook { private int top=0; private static final int MAXENTRIES =100; private AddressBookEntry[] list; public static void main(String[] args){ BufferedReader input= new BufferedReader(new InputStreamReader(System.in)); AddressBook addBook=new AddressBook(); String act=""; while(true){ System.out.println("\n [A] Add entry"); System.out.println("\n [D] Delete entry"); System.out.println("\n [V] View all entries"); System.out.println("\n [U] Update entry"); System.out.println("\n [Q] Quit"); System.out.println("Enter desired action"); try{ act=input.readLine(); }catch(Exception e){ System.out.println("Error"); } if(act.equals("A")||act.equals("a")) addBook.addEntry(); else if(act.equals("D")||act.equals("d")) addBook.deleteEntry(); else if(act.equals("V")||act.equals("v")) addBook.viewEntries(); else if(act.equals("U")||act.equals("u")) addBook.updateEntry(); else if(act.equals("Q")||act.equals("q")) System.exit(0); else System.out.println("Command Unknown"); } } public AddressBook(){ list= new AddressBookEntry[MAXENTRIES]; } public void addEntry() { BufferedReader input= new BufferedReader(new InputStreamReader(System.in)); String name=""; String add=""; int tel=0; String email=""; if(top>=MAXENTRIES){ System.out.println("Address Book is full"); return; } try{ System.out.print("Name: "); name=input.readLine(); System.out.print("Address: "); add=input.readLine(); System.out.print("Telephone number: "); tel=Integer.parseInt(input.readLine()); System.out.print("Email: "); email=input.readLine(); }catch(Exception e){ System.out.println(e); System.exit(0); } AddressBookEntry entry= new AddressBookEntry(name,add,tel,email); list[top]=entry; top++; } public void deleteEntry() { BufferedReader input= new BufferedReader(new InputStreamReader(System.in)); int i=0; if(top==0){ System.out.println("Address Book is empty"); return; } try{ viewEntries(); System.out.println("\n Enter entry number: "); i=Integer.parseInt(input.readLine())-1; }catch(Exception e){} if(i<0 || i>=top){ System.out.println("Index out of bounds"); return; }else{ for(int x=i; x<top; i++){ list[i]=list[i+1]; } list[top]=null; top--; } } public void viewEntries(){ for(int i=0; i<top; i++){ System.out.println((i+1)+"Name: "+list[i].getname()); System.out.println((i+1)+"Address: "+list[i].getAdd()); System.out.println((i+1)+"Telephone Number: "+list[i].getTel()); System.out.println((i+1)+"Email: "+list[i].getEmail()); } } public void updateEntry(){ BufferedReader input= new BufferedReader(new InputStreamReader(System.in)); int i=0; String name=""; String add=""; int tel=0; String email=""; try{ System.out.print("Entry number: "); i=Integer.parseInt(input.readLine())-1; System.out.print("Name: "); name=input.readLine(); System.out.print("Address: "); add=input.readLine(); System.out.print("Telephone number: "); tel=Integer.parseInt(input.readLine()); System.out.print("Email: "); email=input.readLine(); }catch(Exception e){ System.out.println(e); System.exit(0); AddressBookEntry entry= new AddressBookEntry(name,add,tel,email); list[i]=entry; } } }


Here is the error:
cannot find symbol class AddressBookEntry line 8 cannot find symbol class AddressBookEntry line 51 cannot find symbol class AddressBookEntry line 80 cannot find symbol class AddressBookEntry line 80 cannot find symbol class AddressBookEntry line 146 cannot find symbol class AddressBookEntry line 146

OK here is the problem my friend gave:
Get input from the user using command-line arguments and print all the arguments to the screen. For example, if the user entered,

Java Hello world that is all

your program should print

Hello
world
that
is
all


I press shift + f6 to make the program run, I'm using netbeans.O.O