Mohnish Khiani

This is my server code
System.out.println("Setting device to be discoverable..."); local = LocalDevice.getLocalDevice(); local.setDiscoverable(DiscoveryAgent.GIAC); System.out.println(local.getBluetoothAddress()); System.out.println("Start advertising service..."); server = (StreamConnectionNotifier)Connector.open(url); System.out.println("Waiting for incoming connection..."); conn = server.acceptAndOpen(); System.out.println("Client Connected..."); DataInputStream din = new DataInputStream(conn.openInputStream()); DataOutputStream dout = new DataOutputStream(conn.openOutputStream());

This is the code in MIDLet which discovers devices:
public void FindDevices() { try{ devices = new java.util.Vector(); LocalDevice local = LocalDevice.getLocalDevice(); DiscoveryAgent agent = local.getDiscoveryAgent(); agent.startInquiry(DiscoveryAgent.GIAC,this); }catch(Exception e) { System.out.println(e.getMessage()); System.out.println("Device not found"); this.do_alert("Erron in initiating search" , 4000); } }
I have deployed the midlet in my phone.My problem is that the server displays
"Waiting for incoming connection "
And when the mobile searches for the device it is not able to locate any....what do i do to establish the connection?

package packA; public class A { protected int pf; }


package packB; import packA.A; public class B extends A { public void act(A obj1,B obj2,C obj3) { pf=1; //(1) obj1.pf=1; //(2) obj2.pf=2; //(3) obj3.pf=3; //(4) } } public class C extends B { public void act(A obj1,B obj2,C obj3) { pf=1; //(5) obj1.pf=1; //(6) obj2.pf=2; //(7) obj3.pf=3; //(8) } }

There are errors on line :5,6,7,8
and no error on line :3,4

Please explain how ?

when p calls printit(),the object calling it is of class B.
Therefore it calls this.printit() where this is an object of class B.Hence it is like B.printit() and not A.printit() as there is no relationship between printit() of A and B.Please explain???

Whats the logic behind this output ?

public class c { public static void main(String a[]) { b q=new b(); q.printit(); q.p(false); } } class a { private void printit() { System.out.print("Super"); } void p(boolean f) {if(f==true) {System.out.println("Hi"); } else printit(); } } class b extends a {void printit() {System.out.print("Sub"); } }

Output : SubSuper

How?

class exp { public static void main(String a[]) { int j=0; for(int i=0;i<10;i++) { j=j++; } System.out.println(j); } }

Output : 0
How do we get output as 0?

i have executed the code and know the output is 5,but i wanted to know how?

That means evaluation is from left to right no matter pre or post operators?

Whats the order of evaluation?
int i=0; int x=++i + i++ + ++i; System.out.println(x+" "+i);

Output :
5 3

What is the right output :
1+2+2=5
(or)
1+1+3=5

got it...thank you

What and how is this happening?
Integer i1=1000; Integer i2=1000; if(i1!=i2) { System.out.println("i1!=i2"); } Integer i3=10; Integer i4=10; if(i3==i4) { System.out.println("i3==i4"); }

Output :
i1!=i2
i3==i4

public class static_exp { public static void main(String args[]) { hobbit o1=new hobbit(); hobbit_exp o2=new hobbit_exp(); o1.func1(); o2.func1(); o1=o2; o1.func1(); } } class hobbit { int a=1; static void func1() { System.out.println("Static func1 of hobbit"); } } class hobbit_exp extends hobbit { static void func1() { System.out.println("Static func1 of hobbit_exp"); } }

It's output is :
Static func1 of hobbit
Static func1 of hobbit_exp
Static func1 of hobbit

I understand that this is not dynamic polymorphism because which static method is to be invoked depends on the reference type rather than the actual object type....but then what is this called when I can redifine the static method in my subclass....do static methods get inherted?

thank you..I got it

okay,so is this also correct :

B obj=(B)(new A());

That means whichever objects and instance variables can be accessed by o1 can also be accessed by o2....am I right?

class A { } class B extends A { } class C { public static void main(String a[]) { A o1=new B(); A o2=(A)(new B()); } }

What difference would be there in the working of o1 and o2 objects?

Thank You Sir..thanks a lot for your answer